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Elza [17]
2 years ago
8

The game of kickball begins with the ball being rolled toward a player. The player then kicks the ball across the field. What is

true about the speed of the ball when it is kicked?
A.
The speed of the ball is not dependent on the force used to kick it.

B.
The speed of the ball will be slower than the speed at which it was pitched.

C.
The speed of the ball depends on the force used to kick it.

D.
The speed of the ball mostly depends on the speed at which it was pitched.
which is correct
Chemistry
2 answers:
hammer [34]2 years ago
6 0

Answer:

C. The Speed of the ball depends on the force used to kick it.

Explanation:

Olegator [25]2 years ago
4 0

Answer:

d is correct

Explanation:

a ball loses some force of the pitch when touching a solid object and so

D.

The speed of the ball mostly depends on the speed at which it was pitched.

which is correct

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arsen [322]

Answer:

The answer is A

Explanation:

5 0
3 years ago
S
N76 [4]

Answer:

B

Explanation:

B

4 0
2 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
All modern fertilizers use PO43- as a source of phosphorus. Use your knowledge of the old methods to determine the moles of phos
tamaranim1 [39]

Answer:

The answer is 0.023 moles of phosphorus

Explanation:

The 15-15-15 fertilizer is a fertilizer of great versatility, made with nitrogen, phosphorus and potassium, which makes it one of the fertilizers most used for fertilizer in the sowing plant, thus covering the crop requirements from planting. .

This fertilizer consists of 14.25% phosphorus pentoxide (P2O5). Therefore, we have to remove 14.25% at 10 grams of 15-15-15 fertilizer to calculate the moles of phosphorus. As follows:

Grams of P2O5 = 10 g x 0.1425 = 1.425 g

We calculate the molecular weight of phosphorus. We use the periodic table:

Phosphorus molecular weight = 2 x 30.97 = 61.94 g/mol

Now we calculate the moles of phosphorus in the fertilizer:

Phosphorus moles = 1,425 g/61.94 g/mol = 0.023 moles

8 0
2 years ago
The chemical formula tells the types of atoms and how many of each are contained in a compound. Please select the best answer fr
kykrilka [37]
The anser should be false

7 0
3 years ago
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