a) The sizes of punch and blanking are equivalent to its diameters. The blanking die diameter is Db = 65 mm
Diameter of the blanking punch is,
dpunch = Db - 2c
Here, c = Ac (thickness)
For aluminium, Ac = 0.06
c = (0.06) (3.2 mm) = 0.192 mm
dpunch = (65 mm) - 2 (0.192 mm)
= 64.616 mm
b) The diameter of the punching punch is equivalent to the interior diameter of the washer.
Thus, diameter of the punching die is, Dh = 30 mm
Diameter of the punching die is,
ddie = Dh + 2c
= (30 mm) + 2 (0.192)
= 30.384 mm
The answer
would be 825000
Hope it helps!
Consider the reaction
<span>2Al(OH)3(s)→Al2O3(s)+3H2O(l) </span>
<span>with enthalpy of reaction </span>
<span>ΔHrxn∘=21.0kJ/mol </span>
<span>What is the enthalpy of formation of Al2O3(s)? </span>
<span>Substance ΔHf∘ (kJ/mol) </span>
<span>HCl(g) −92.0 </span>
<span>Al(OH)3(s) −1277.0 </span>
<span>H2O(l) −285.8 </span>
<span>AlCl3(s) −705.6 </span>
<span>H2O(g) −241.8</span>
Answer:
The limiting reactant is the copper
Explanation:
Moles are the standard unit at which you can compare values, and copper has fewer moles than Silver nitrate, so in a reaction, it would be used up first, leaving Silver nitrate in excess.
mol CO₂ = 9.6
mol N₂ = 4.8
mol O₂ = 0.8
mol H₂O = 8
<h3>Further explanation</h3>
Reaction
4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O
mol CO₂
mol N₂
mol O₂
mol H₂O
