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alexira [117]
3 years ago
8

A bag contains 6 red balls 8 yellow ones and 4 black ones if a ball is randomly selected find the probability of it being neithe

r black nor yellow
A 2
9
B 5
9
C 7
9
D 1
3
E 4
9
Mathematics
1 answer:
Natali [406]3 years ago
3 0

Answer:

1/3

(given answers in Question are unreadable)

Step-by-step explanation:

We search for red balls (neither yellow or black). There are 6 red balls among all 18 balls. Selecting one ball, there is a chance 6/18 that we pull out a red one. 6/18 is the same as 1/3.

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An equation is shown. x + 3 = 8.5 what is the solution to the equation
skad [1K]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Y=-8x-4 for what value of x is y equal too -16
boyakko [2]

Answer: X=1.5

Step-by-step explanation:

The equation when y is -16

-16=-8x-4

-12=-8x

12/8 is 1.5

8 0
3 years ago
Find the exact solutions to 2x^2=5x-1 by using the quadratic formula
Luda [366]

Solve the equation for  x  by finding  a ,  b , and  c of the quadratic then applying the quadratic formula

Exact form:

x =  5 ± √ 17

     4

Decimal:

x =  2.28077640 … , 0.21922359

sorry idk how to put a fraction in

3 0
3 years ago
Read 2 more answers
Help on this? thanks (:
Alex

Answer:

D

Step-by-step explanation:

24-6 = 18 32-6x3=18

Hope this helped!

4 0
3 years ago
Read 2 more answers
Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=​
Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

8 0
3 years ago
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