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musickatia [10]
3 years ago
6

The combination reagents that can be used to distinguish between ethane, ethene and ethyne are?​

Chemistry
1 answer:
mafiozo [28]3 years ago
5 0

Answer:

Two reagents that can be used to distinguish between ethane and ethyne are Tollens' reagent and ammoniacal CuCl solution.

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AfilCa [17]

Answer:

the fourth one I think....m

Explanation:

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7 0
2 years ago
1. Which of the following statements is NOT true about double-replacement reactions?
SSSSS [86.1K]
1 is D - double-replacements do not make solid metals
2 is A - to have complete combustion the original compound must ONLY have C, H and O
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7 0
3 years ago
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How many grams are in 4.5 x 10^22 molecules of Ba(NO2)2
NNADVOKAT [17]

Answer:

17 g Ba(NO₂)₂

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

4.5 × 10²² molecules Ba(NO₂)₂

<u>Step 2: Define conversion</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol

<u>Step 3: Dimensional Analysis</u>

<u />4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )

= 17.1384 g Ba(NO₂)₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂

7 0
2 years ago
Explain how you can obtain hydrated sodium sulphate crystals from an aqueous solution of sodium sulphate​
Mice21 [21]

Answer:

If you left your aqueous sodium sulfite solution open on the side, atmospheric oxygen would cause the chemical change, the water would hydrate the new compound and the slow evaporation of water would give you lovely large crystals of Na2SO4 without you having to do anything!

6 0
3 years ago
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Which of the following is the main reason to use titration in chemistry?
Dmitrij [34]
<span>to find the molarity of an unknown acid or base</span>
8 0
3 years ago
Read 2 more answers
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