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2 years ago

Help pls I don’t understand the question.

Engineering

1 answer:

REY [17]2 years ago

3 0

Answer:

I think it's asking what the area is when it says A=

when it says d= it means diameter

so for the first one, I believe the answer would be 28.27

and the second one would be 0.79

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A shunt regulator utilizing a zener diode with an incremental resistance of 8 ohm is fed through an 82-Ohm resistor. If the raw

spayn [35]

Answer:

$\triangle V_0=0.08V$

Explanation:

From the question we are told that:

Incremental resistance $R=8ohms$

Resistor Feed $R_f=82ohms$

Supply Change $\triangle V=1$

Generally the equation for voltage rate of change is mathematically given by

$\frac{dV_0}{dV}=\frca{R}{R_1r_3}$

Therefore

$\triangle V_0=\triangle V*\frac{R}{R_fR}$

$\triangle V_0=1*\frac{8}{8*82}$

$\triangle V_0=0.08V$

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2 years ago

A water reservoir contains 108 metric tons of water at an average elevation of 84 m. The maximum amount of electric energy that

zavuch27 [327]

Answer:

24.72 kwh

Explanation:

Electric energy=potential energy=mgz where m is mass, g is acceleration due to gravity and z is the elevation.

Substituting the given values while taking g as 9.81 and dividing by 3600 to convert to per hour we obtain

PE=(108*9.81*84)/3600=24.72 kWh

8 0

3 years ago

Bending is defined as? A. the application of a load tending to distort a member in one direction. B. the application of opposing

amm1812

Hi how are you today

4 0

2 years ago

If we have silicon at 300K with 10 microns of p-type doping of 4.48*10^18/cc and 10 microns of n-type doping at 1000 times less

liq [111]

Answer:

The resistance is 24.9 Ω

Explanation:

The resistivity is equal to:

$R=\frac{1}{N_{o}*u*V } =\frac{1}{4.48x10^{15}*1500*106x10^{-19} } =0.93ohm*cm$

The area is:

A = 60 * 60 = 3600 um² = 0.36x10⁻⁴cm²

$w=\sqrt{\frac{2E(V_{o}-V) }{p}(\frac{1}{N_{A} }+\frac{1}{N_{D} })$

If NA is greater, then, the term 1/NA can be neglected, thus the equation:

$w=\sqrt{\frac{2E(V_{o}-V) }{p}(\frac{1}{N_{D} })$

Where

V = 0.44 V

E = 11.68*8.85x10¹⁴ f/cm

$V_{o} =\frac{KT}{p} ln(\frac{N_{A}*N_{D}}{n_{i}^{2} } , if n_{i}=1.5x10^{10}cm^{-3} \\V_{o}=0.02585ln(\frac{4.48x10^{18}*4.48x10^{15} }{(1.5x10^{10})^{2} } )=0.83V$

$w=\sqrt{\frac{2*11.68*8.85x10^{-14}*(0.83-0.44) }{1.6x10^{-19}*4.48x10^{15} } } =3.35x10^{-5} cm=0.335um$

The length is:

L = 10 - 0.335 = 9.665 um

The resistance is:

$Re=\frac{pL}{A} =\frac{0.93*9.665x10^{-4} }{0.36x10^{-4} } =24.9ohm$

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2 years ago

4. The outer end of a control arm is attached to the steering knuckle through a

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Is attached to the spring

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2 years ago

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