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3 years ago

The best approach to keeping your car in safe working order is to

Engineering

2 answers:

vovikov84 [41]3 years ago

6 0

Answer:

Explanation:

In order to keep your car running at its best, it’s important to keep up with routine maintenance and inspections. By properly maintaining your vehicle, you’ll reduce future repair costs, optimize your car’s performance, maintain its value and extend its life. Here are some regular maintenance needs to keep in mind for your vehicle:

svp [43]3 years ago

5 0

Answer:

Preventive Maintenance

Explanation:

Constant preventive maintenance is the best way to keep cars in check irrespective of the status of the car. Constantly checking the Oil, filters, tire gauge etc, are also part of the best approach to keeping your car in safe working order.

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melinda is using a rectangular brass bar in a sculpture she is creating. the brass bar has a length that is 4 more than 3 times

lawyer [7]

Answer:

180 x 60 inches

Width = 60 inches

Length = 180 inches

Explanation:

Given

Let L = Length

W = Width

P = Perimeter

Length = 3 * Width

L = 3W

Perimeter of Brass = 480 inches

P = 480

Perimeter is given as 2(L + W);

So, 2 (L + W) = 480

L + W = 480/2

L + W = 240

Substitute 3W for L; so,

3W + W = 240

4W = 240

W = 240/4

W = 60 inches

L = 3W

L = 3 * 60

L = 180 inches

6 0

3 years ago

Read 2 more answers

A silicon diode has a saturation current of 6 nA at 25 degrees Celcius. What is the saturation current at 100 degrees Celsius?

Illusion [34]

Answer:

0.0659 A

Explanation:

Given that :

$I_{0} = 6nA$ ( saturation current )

at 25°c = 300 k ( room temperature )

n = 2 for silicon diode

Determine the saturation current at 100 degrees = 373 k

Diode equation at room temperature = I = Io $\frac{V}{e^{0.025*n} }$

next we have to determine the value of V at 373 k

q / kT = (1.6 * 10^-19) / (1.38 * 10^-23 * 373) = 31.08 V^-1

Given that I is constant

Io = $\frac{e^{0.025*2} }{31.08}$ = 0.0659 A

3 0

3 years ago

Strands of materials A and B are placed under a tensile force of 10 Newtons. Material A deforms more than Material B.

nadezda [96]

Answer:

True

Explanation:

6 0

3 years ago

Read 2 more answers

A 100 ft long steel wire has a cross-sectional area of 0.0144 in.2. When a force of 270 lb is applied to the wire, its length in

blondinia [14]

Answer:

(a) The stress on the steel wire is 19,000 Psi

(b) The strain on the steel wire is 0.00063

Explanation:

Given;

length of steel wire, L = 100 ft

cross-sectional area, A = 0.0144 in²

applied force, F = 270 lb

extension of the wire, e = 0.75 in

Part (A) The stress on the steel wire;

δ = F/A

= 270 / 0.0144

δ = 18750 lb/in² = 19,000 Psi

Part (B) The strain on the steel wire;

σ = e/ L

L = 100 ft = 1200 in

σ = 0.75 / 1200

σ = 0.00063

Part (C) The modulus of elasticity of the steel

E = δ/σ

= 19,000 / 0.00063

E = 30,000,000 Psi

4 0

3 years ago

Question 2 (Multiple Choice Worth 3 points)

ololo11 [35]

Answer:

the car to the right

Explanation:

its in the name the RIGHT of way hope it helps good luck

6 0

3 years ago