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Sloan [31]
3 years ago
10

The density of a certain material is such that it weighs 9 pounds per cubic foot of

Engineering
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

The answer is "101"

Explanation:

Given value:

We must convert density into pounds per cubic foot to 6900 grams per 4.5 quarter of the length.

1\  \text{Liquid quart} = 0.03342 \ \text{cubic foot} \\\\1 \ \text{gram} = 0.0022 \ \text{pound}\\

Formula:

\bold{density = \frac{6900}{4.5} \frac{gram}{quart}}\\

=\frac{6900 \times 0.0022 \ pound }{4.5 \times 0.03342 \cubic \ foot}\\\\= \frac{15.2119}{0.15039} \\\\= 101.1497 \ or \ 101 \ \text{pound per cubic feet}\\

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2 years ago
Brazing, Soldering and Adhesive Bonding are the types of • Liquid Solid System Welding Solid State Welding • Fusion Welding . No
olga_2 [115]

Answer: Solid state welding

Explanation: Solid state welding is the welding procedure which is based on the temperatures and pressure but without any liquid or vapor as aid for welding.This process is carried mainly cohesive forces and considering forces as less important. Brazing,soldering and adhesive is the process in which material are joint which the help of solid welding agent.Thus solid state welding is the correct option.

6 0
2 years ago
Calculate the wire pressure for a round copper bar with an original cross-sectional area of 12.56 mm2 to a 30% reduction of area
dybincka [34]

Answer:153.76 MPa

Explanation:

Initial Area\left ( A_0\right )=12.56 mm^2

Final Area\left ( A_f\right )=0.7\times 12.56 mm^2=8.792 mm^2

Die angle=30^{\circ}

\alpha =\frac{30}{2}=15^{\circ}

\mu =0.08

Yield stress\left ( \sigma _y \right )=350 MPa

B=\mu cot\left ( \aplha\right )=0.2985

\sigma _{pressure}=\sigma _y\left [\frac{1+B}{B}\right ]\left [ 1-\frac{A_f}{A_0}\right ]^B

\sigma _{pressure}=350\left [\frac{1+0.2985}{0.2985}\right ]\left [ 1-\frac{8.792}{12.56}\right ]^{0.2985}

\sigma _{pressure}=153.76 MPa

8 0
3 years ago
The following electrical characteristics have been determined for both intrinsic and p-type extrinsic gallium antimonide (GaSb)
xxTIMURxx [149]

Answer:

0.5m^2/Vs and 0.14m^2/Vs

Explanation:

To calculate the mobility of electron and mobility of hole for gallium antimonide we have,

\sigma = n|e|\mu_e+p|e|\mu_h (S)

Where

e= charge of electron

n= number of electrons

p= number of holes

\mu_e= mobility of electron

\mu_h=mobility of holes

\sigma = electrical conductivity

Making the substitution in (S)

Mobility of electron

8.9*10^4=(8.7*10^{23}*(-1.602*10^{-19})*\mu_e)+(8.7*10^{23}*(-1.602*10^{-19})*\mu_h)

0.639=\mu_e+\mu_h

Mobility of hole in (S)

2.3*10^5 = (7.6*10^{22}*(-1.602*10^{-19})*\mu_e)+(1*10^{25}*(-1.602*10^{-19}*\mu_h))

0.1436 = 7.6*10^{-3}\mu_e+\mu_h

Then, solving the equation:

0.639=\mu_e+\mu_h (1)

0.1436 = 7.6*10^{-3}\mu_e+\mu_h (2)

We have,

Mobility of electron \mu_e = 0.5m^2/V.s

Mobility of hole is \mu_h = 0.14m^2/V.s

6 0
3 years ago
The increasing interconnections of peoples and countries around the world is known as ________.
Irina18 [472]
I think it’s rationalization.
Hope this helps
4 0
3 years ago
Read 2 more answers
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