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2 years ago

The density of a certain material is such that it weighs 9 pounds per cubic foot of

Engineering

1 answer:

My name is Ann [436]2 years ago

8 0

Answer:

The answer is "101"

Explanation:

Given value:

We must convert density into pounds per cubic foot to 6900 grams per 4.5 quarter of the length.

$1\ \text{Liquid quart} = 0.03342 \ \text{cubic foot} \\\\1 \ \text{gram} = 0.0022 \ \text{pound}\\$

Formula:

$\bold{density = \frac{6900}{4.5} \frac{gram}{quart}}\\$

$=\frac{6900 \times 0.0022 \ pound }{4.5 \times 0.03342 \cubic \ foot}\\\\= \frac{15.2119}{0.15039} \\\\= 101.1497 \ or \ 101 \ \text{pound per cubic feet}\\$

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what can be done to prevent bridges from collapsing? ( give at least two examples)

ryzh [129]

Explanation:

the owner of the bridge and some workers

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2 years ago

A insulated vessel s has two compartments separated by a membreane. On one side is 1kg of steam at 400 degC and 200 bar. The oth

Lilit [14]

Answer:

See explaination

Explanation:

See attachment for the detailed step by step solution of the given problem.

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2 years ago

A long, circular aluminum rod is attached at one end to a heated wall and transfers heat by convection to a cold fluid.

Trava [24]

Answer:

a. Heat removal rate will increase

b. Heat removal rate will decrease

Explanation:

Given that

One end of rod is connected to the furnace and rod is long.So this rod can be treated as infinite long fin.

We know that heat transfer in fin given as follows

$Q_{fin}=\sqrt{hPKA}\ \Delta T$

We know that area

$A=\dfrac{\pi}{4}d^2$

Now when diameter will triples then :

$A_f=\dfrac{\pi}{4}{\left (3d \right )}^2$

$A_f=9A$

$Q'_{fin}=\sqrt{9hPKA}\ \Delta T$

$Q'_{fin}=3\sqrt{hPKA}\ \Delta T$

$Q'_{fin}=3Q$

So the new heat transfer will increase by 3 times.

Now when copper rod will replace by aluminium rod :

As we know that thermal conductivity(K) of Aluminium is low as compare to Copper .It means that heat transfer will decreases.

3 0

2 years ago

How many trips would one rubber-tired Herrywampus have to make to backfill a space with a geometrical volume of 5400 cubic yard?

nikklg [1K]

Answer:

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

Explanation:

a) By volume.

The shrinkage factor is:

$\frac{5400cu-yd}{1-0.25} =7200cu-yd$

The volume at loose is:

$V_{loose} =V_{bank} (1+swell-factor)=7200(1+0.2)=8640cu-yd$

If the Herrywampus has a capacity of 30 cubic yard:

$\frac{8640cu-yd}{30cu-yd/trip} =288trip$

b) By weight

The swell factor in terms of percent swell is equal to:

$pounds-per-cubic-yard-loose=\frac{pounds-per-cubic-yard-bank}{\frac{percent-swell}{100}+1 }$

$pounds-per-cubic-yard-loose=\frac{3000}{\frac{20}{100} +1} =2500lb/cu-yd$

The weight of backfill is:

$8640cu-yd*2500\frac{lb}{cu-yd} *\frac{1ton}{2000lb} =10800ton$

The Herrywampus has a capacity of 40 ton:

$\frac{10800}{40ton/trip} =270trip$

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

8 0

2 years ago

Name the five points where product should be scanned during it's path throughout the warehouse.

Oxana [17]

Answer and Explanation:

A warehouse can be defined as a place:

is a spot or building, where the articles are kept, put away or in some cases prepared.

Depending on the sort of use, the checkpoints may fluctuate.

There can be numerous sorts, for example, pressing, railroad wagon, cool stockpiling, and so on.

Suppositions are caused in regards to each shape and a few checkpoints for an item to can be summed up.

The point of entry, where it ought to be through into the product house.

Security checkpoint, where the item belonging is to be protected.

Palletized segment, where the item is to be put in a spot and it determines the location of that item in the house.

Quality or bundling segment, where the item must be tried and improved.

Leave segment, through which it must be taken out for further procedures.

7 0

3 years ago