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3 years ago

The density of a certain material is such that it weighs 9 pounds per cubic foot of

Engineering

1 answer:

My name is Ann [436]3 years ago

8 0

Answer:

The answer is "101"

Explanation:

Given value:

We must convert density into pounds per cubic foot to 6900 grams per 4.5 quarter of the length.

$1\ \text{Liquid quart} = 0.03342 \ \text{cubic foot} \\\\1 \ \text{gram} = 0.0022 \ \text{pound}\\$

Formula:

$\bold{density = \frac{6900}{4.5} \frac{gram}{quart}}\\$

$=\frac{6900 \times 0.0022 \ pound }{4.5 \times 0.03342 \cubic \ foot}\\\\= \frac{15.2119}{0.15039} \\\\= 101.1497 \ or \ 101 \ \text{pound per cubic feet}\\$

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What is the power system?

Inessa [10]

Answer: An electric power system is a network of electrical components deployed to supply, transfer, and use electric power.

Explanation:

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4 years ago

A simple undamped spring-mass system is set into motion from rest by giving it an initial velocity of 100 mm/s. It oscillates wi

____ [38]

Answer:

f=1.59 Hz

Explanation:

Given that

Simple undamped system means ,system does not consists any damper.If system consists damper then it is damped spring mass system.

Velocity = 100 mm/s

Maximum amplitude = 10 mm

We know that for a simple undamped system spring mass system

$V_{max}=\omega A$

now by putting the values

$V_{max}=\omega A$

100 = ω x 10

ω = 10 rad/s

We also know that

ω=2π f

10 = 2 x π x f

f=1.59 Hz

So the natural frequency will be f=1.59 Hz.

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4 years ago

An 18-in.-long titanium alloy rod is subjected to a tensile load of 24,000 lb. If the allowable tensile stress is 60 ksi and the

Vilka [71]

Answer:

Required Diameter = 302.65 inches

Explanation:

We are given;

Allowable tensile stress = 60 ksi

Weight of tensile load = 24,000 lb

Elongation = 0.05 in

Original length = 18 in

We'll need to check the diameters under stress and strain.

Now, we know that the formula for stress is;

Stress = Force/Area

Thus,

Area = Force/stress

So for this stress, area required is;

A_req = 24000/60 = 4000 in²

So let's find the required diameter here.

Area = πd²/4

So, 4000 = πd²/4

(4000 x 4)/π = d²

d² = 5092.96

Required diameter here is;

d = √5092.96

d = 71.36 in

For Strain;

Formula for strain is;

Strain = stress/E

We are given E = 120 ksi

stress = P/A = 24,000/A

strain = elongation/original length = 0.05/18 = 0.00278

Thus;

0.00278 = P/(A•E)

0.00278 = 24000/(120 x A)

Making A the subject to obtain;

A = 24000/(120 x 0.00278)

A_required = 71942 in²

Area = πd²/4

So, 71942 = πd²/4

(71942 x 4)/π = d²

d² = 91599.4

Required diameter here is;

d = √91599.4

d = 302.65 in

The larger diameter is 302.65 inchesand it's therefore the required one.

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4 years ago

7. An energy auditor is part of what career field?

Rashid [163]

An energy auditor is part of power operations

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2 years ago

A receptacle, plug, or any other electrical device whose design limits the ability of an electrician to come in contact with any

o-na [289]

Answer:

Recessed safe

Explanation:

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A recessed outlet is also more ideal than standard outlets where there are hazards such as potential contact with water.

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3 years ago