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aliina [53]
3 years ago
6

A step-down transformer (turns ratio = 1:7) is used with an electric train to reduce the voltage from the wall receptacle to a v

alue needed to operate the train. When the train is running, the current in the secondary coil is 1.04 A. What is the current in the primary coil?
Engineering
1 answer:
SOVA2 [1]3 years ago
6 0

Answer:

wait lemme check it out

Explanation:

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Problema sobre programacion orientada a objetos!!
Alecsey [184]

Answer:If they are used to top-down programming or functional programming, which treats elements of code as precise mathematical functions, it takes .

Explanation:

8 0
3 years ago
If you install special sound-reflecting windows that reduce the sound intensity level by 33.0 dBdB , by what factor have you red
Sever21 [200]

Answer:

The sound intensity is reduced by a factor of 1995.26

Explanation:

When comparing two sound intensities, the intensity level is measured in the unit of decibel or dB. The intensity of the threshold of hearing for a human being is  10^−12 W/m^2 . When the intensity level is zero, it means that the sound intensity is the same as the threshold of hearing.

The reduced sound intensity level is given as 33 dB, so

10  log (I/Io)  = - 33

I  : intensity of the sound

Io ( =   10^−12 W/m^2): threshold of hearing

So, the intensity ratio is

I/Io = 10^-3.3

     = 5.01 x 10^-4

1/ 5.01 x 10^-4 = 1995.26

3 0
4 years ago
One of the best ways to increase engine power and control detonation and preignition is to?
Reika [66]

Answer:

use water injection.

8 0
1 year ago
A piston-cylinder device with 15 lbm of steam is heated from a temperature and pressure of 500 °F and 350 psia to a new temperat
nevsk [136]

Answer:

The work done is 1050 Btu

Solution:

As per the question:

Mass of steam, M = 15 lbm

Temperature, T = 500^{\circ}F

Temperature, T' = 600^{\circ}F

Pressure, P = 350 psia

Since, the process results in the change in volume at constant pressure.

Now, work done by the steam is given by;

W = \int_{V}^{V'} P dU

And

U = mV

So,

W = m\int_{V}^{V'} P dV

W = mP(V' - V)           (1)

Now, using the super heated vapor table:

At 350 psia and 500^{\circ}F,  V = 1.5 ft^{3}/lb

At 350 psia and 600^{\circ}F,  V' = 1.7 ft^{3}/lb

Now, using these values in eqn(1):

W = 15\times 350(1.7 - 1.5) = 1050 Btu

4 0
3 years ago
A solar radiation flux of 700 W/m2 is absorbed in a metal plate that is perfectly insulated on the back surface. The convection
skad [1K]

Answer:

The main solution to this problem is to note that under equilibrium conditions, the rate at which heat is transferred into the metal plate from the sun by radiation must be equal to the rate at which heat is lost from the plate to the surrounding air by convection.

Explanation:

Therefore, qᵃ = qᵇΔT

where

a = Radiation energy source

b = Convection energy source

ΔT = Tp - Ta = Temperature change between the plate and the air under equilibrium condition

Given,

qᵃ = 700 W/m2

qᵇ = 10 W/m2K - 100 W/m2K

Hence, for qᵇ = 10 W/m2K,

        ΔT = qᵃ / qᵇ

        ΔT = 700/10 = 70K

Similarly, for qᵇ = 100 W/m2K

              ΔT = 700/100 = 7K

The temperature change of the plate under equilibrium conditions range from 7K to 70K.

4 0
4 years ago
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