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Fantom [35]
3 years ago
13

The bulk modulus of a material is 3.5 ✕ 1011 N/m2. What percent fractional change in volume does a piece of this material underg

o when it is subjected to a bulk stress increase of 107 N/m2? Assume that the force is applied uniformly over the surface.
Engineering
1 answer:
kiruha [24]3 years ago
6 0

Answer:

percentage change in volume  = 0.00285 %

Explanation:

given data

bulk modulus = 3.5 × 10^{11}  N/m²

bulk stress = 10^{7}  N/m²

solution

we will apply here bulk modulus formula that is

bulk modulus = \frac{bulk\ stress}{bulk\ strain}   ...............1

put here value and we get

3.5 × 10^{11} = \frac{10^7}{bulk\ strain}  

solve it we get

bulk strain = 2.8571 × 10^{-5}

and

bulk strain = \frac{change\ volume}{original\ volume}  

so that percentage change in volume is = 2.8571 × 10^{-5}  × 100

percentage change in volume  = 0.00285 %

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Answer:

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Explanation:

given data

pressure = 4 MPa

specific enthalpy h1 = 3015.4 kJ/kg

velocity v1 = 10 m/s

pressure = 0.07 MPa

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velocity v2 = 90 m/s

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solution

we apply here  thermodynamic equation that

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h1 + \frac{v1}{2}  + q = h2 + \frac{v2}{2}  + w

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3015.4 *1000 + \frac{10^2}{2}  =  2431.7 * 1000 + \frac{90^2}{2}  + w

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3 years ago
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A hair dryer is basically a duct in which a few layers of electric resistors are placed. A small fan pulls the air in and forces
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Answer:

a) volume flow rate of air at the inlet is 0.0471 m³/s

b) the velocity of the air at the exit is  8.517 m/s

Explanation:

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Inlet temperature of air T_in = 22°C

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Exit temperature T_out = 47°C

Exit area of the dyer is A_out = 60 cm²= 0.006 m²

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R = 0.287 kPa·m3/kg·K

Using mass balance

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we know that h = CpT

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W _elec = m_air.Cp ( T_in - T_out)

we substitute

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m_air = -1.4 / - 25.175

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we know that

m_air = P_in × V_in

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P_in = p_in / RT_in

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b) velocity of the air at the exit

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m_ air = P_in.A_in.V_in = P_out.A_out.V_out

still from the ideal gas equation

P_out = p_out/ RT_out   ( assume p_in = p_out)

P_out = (100×10³) / ((0.287×10³)(47+273))

P_out  = 1.088 kg/m³

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V_out = m_air / P_out.A_out

we substitute our values

V_out = 0.0556 / ( 1.088 × 0.006)

= 0.0556 / 0.006528

= 8.517 m/s

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