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Sunny_sXe [5.5K]
3 years ago
10

How does the structure of the stigma aid in pollination?

Chemistry
1 answer:
inysia [295]3 years ago
4 0
If the stigma is messed up it is hard for bees or insects to pollinate because the way they pollinate is by eating the nectar from the stigma and stick the pollen on their body and stick it on the stigma.

But if there is no stigma=no pollination
A good example of a model is a lily
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Describe the particles of a solid, liquid, and gas. For each, be sure to tell how far apart they are and how fast or slowly they
Art [367]

Answer:

Solid

  • A solid is a state of matter where the particles are tightly packed together, they are very close together
  • They vibrate, they move very slowly

Liquid

  • A liquid has free-flowing particles, but they may not leave the container
  • They move at medium speed

Gas

  • <u><em>A gas moves very freely, they leave the container, and they may not be captured in its entirety</em></u>
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<u><em></em></u>

Hope this helps :)

- jp524

3 0
2 years ago
Terms that have to be used: Products, Reactants, Balanced, Unbalanced, Atoms
emmainna [20.7K]

Answer:

A Chemical equation is balanced if the reactants side of the chemical reaction has the same number total of atoms of elements as the products side of the chemical equation. While a Chemical equation is unbalanced if the reactants side of the chemical reaction has a different number total of atoms of elements as the products side of the chemical equation

Explanation:

Self explanatory

3 0
3 years ago
Whats 2 + 2? correct answers only
spayn [35]

9

Explanation:

cause 2 + 2 is equal to 9

3 0
3 years ago
Read 2 more answers
-QUESTION 5-
vodomira [7]
The tall trees much of the sun
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5 0
2 years ago
How much energy is required to vaporize 48.7 g of dichloromethane (CH2Cl2) at its boiling point, if its ΔHvap is 31.6 kJ/mol?
BartSMP [9]

Answer:

The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point

Explanation:

To solve the above question we have the given variable as follows

ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole

However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.

The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles

Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ

3 0
3 years ago
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