The balanced reaction is:<span>
Mg (s) + 2HCl (aq)
--> MgCl 2 (aq) + H 2 (g)
We
are given the amount hydrochloric acid to be used for the reaction. This will
be the starting point of the calculation.
40.0 g
HCl ( 1 mol HCl / 36.46 g HCl)
(1 mol H2 / 2 mol HCl) (2.02 g H2 / 1 mol H2) = 1.11 g H2</span>
Answer:
V CH3OH = 262.5 mL
Explanation:
- %v/v = (v compound / v sln)×100
∴ %v/v = 21.0 %
∴ v sln = 1.25 L
⇒ v compound = ?
⇒ 21.0 % = ( v compound / 1.25)×100
⇒ 0.21 = v compound / 1.25 L
⇒ (0.21)*(1.25 L) = v compound
⇒ v compound = 0.2625 L = 262.5 mL
I think it's an Alkaline Solution