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liq [111]
3 years ago
15

A uniform disk, such as a record turntable, turns at 5.0 rev/s around a frictionless spindle. A nonrotating rod, of the same mas

s as the disk and length equal to the disk's diameter, is dropped onto the freely spinning disk. They then both turn around the spindle with their centers superposed. What is the angular velocity in rev/s of the combination?
Physics
1 answer:
gogolik [260]3 years ago
5 0

Answer:

w=3rev/s

Explanation:

The motion has two steps so is going to be before and after analysis

Before:

L=I*w

L=\frac{1}{2}*m*R^2*w

L=\frac{1}{2}*m*R^2*\pi *f

After:

L'=\frac{1}{2}*m*R^2*w+\frac{1}{12}*m*R^2*w

m*R^2w'*(\frac{1}{2}+\frac{1}{3})

\frac{5}{6}*m*R^2*\pi*f'

Angular momentum is conserved

L=L'

L=\frac{1}{2}*m*R^2*\pi *f=\frac{5}{6}*m*R^2*2*\pi *f'

f'=\frac{6}{10}*5rev/s

w=3rev/s

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Sunlight, with an intensity of 667 W / m², strikes a flat collecting surface perpendicularly and is totally absorbed. The area o
alexandr1967 [171]

Answer:

F = 20.07 μN

Explanation:

given,                                            

intensity of sunlight = 667 W/m²

area of surface =  9.03 m²

speed of light = 3 x 10⁸ m/s

force = ?                                  

we know                                                                

force =intensity \times \dfrac{Area}{speed of light}

force =667 \times \dfrac{9.03}{3\times 10^8}

F = 20.07 x 10⁻⁶ N

F = 20.07 μN

6 0
4 years ago
A simple pendulum is made from a 0.54-m-long string and a small ball attached to its free end. The ball is pulled to one side th
Serga [27]

Answer:

0.37sec

Explanation:

Period of oscillation of a simple pendulum of length L is:

T = 2 π × √ (L /g)

L=length of string 0.54m

g=acceleration due to gravity

T-period

T = 2 x 3.14 x √[0.54/9.8]

T = 1.47sec

An oscillating pendulum, or anything else in nature that involves "simple harmonic" (sinusoidal) motion, spends 1/4 of its period going from zero speed to maximum speed, and another 1/4 going from maximum speed to zero speed again, etc. After four quarter-periods it is back where it started.

The ball will first have V(max) at T/4,

=>V(max) = 1.47/4 = 0.37 sec

3 0
4 years ago
A car of mass 800 kg is moving at a uniform velocity of 72 km/hr. Find its
kenny6666 [7]

Answer:

P = 16,000 kgm/s

Explanation:

<u><em>Given :</em></u>

Mass = m = 800 kg

Velocity = v = 72 km/hr = 20 m/s

<u><em>Required :</em></u>

Momentum = P = ?

<u><em>Formula:</em></u>

P = mv

<u><em>Solution:</em></u>

P = (800)(20)

P = 16,000 kgm/s

5 0
3 years ago
Read 2 more answers
How do the conditions in tube c prevent air reaching the iron nail​
lina2011 [118]

Answer:

The conditions stop air from getting to the nail is the oil

Explanation:

8 0
3 years ago
Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 2.00 cm from the axis to equal
MAXImum [283]

Answer:

Angular velocity of an ultra centrifuge is 17146.42 rad/s.

Explanation:

Given that,

Acceleration of an ultra centrifuge, a=6\times 10^5\ g=6\times 10^5\times 9.8=5.88\times 10^6\ rad/s2

Distance from axis, r = 2 cm = 0.02 m

We need to find the angular speed. We know that the relation between angular speed and angular acceleration is given by :

a=r\omega^2\\\\\omega=\sqrt{\dfrac{a}{r}} \\\\\omega=\sqrt{\dfrac{5.88\times 10^6}{0.02}} \\\\\omega=17146.42\ rad/s

So, the angular velocity of an ultra centrifuge is 17146.42 rad/s.

3 0
4 years ago
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