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2 years ago

14

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total

of 11 people took the trip. She was
able to purchase coach tickets for $330 and first class tickets for $1110. She used her total budget for airfare for the trip, which was $8310. How many first class
tickets did she buy? How many coach tickets did she buy?
number of first class tickets bought

2 answers:

oksano4ka [1.4K]2 years ago

6 0

Answer:

6 first class 5 coach

Step-by-step explanation:

msg me if you need me to explain it

lesya [120]2 years ago

3 0

Answer: 8 First class tickets

Step-by-step explanation:

You can set up a system of equations for this problem. Let x = number of coach tickets and y = number of first class tickets. Then:

330x + 1220y = 12730 (cost of coach tickets plus cost of first class tickets is total budget)

x + y = 17 (number of coach tickets plus number of first class tickets is total number of people)

Solve the second equation for y to get y = 17 - x, then plug that into the first equation and solve for x:

330x + 1220(17 - x) = 12730

330x + 20740 - 1220x = 12730

-890x + 20740 = 12730

-890x = -8010

x = 9

Sarah bought x = 9 coach tickets. Plug that into the second equation and solve for y:

9 + y = 17

y = 8

Sarah bought y = 8 first class tickets.

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For every 4 cups of red paint, $\frac{16}{10}$ cups of blue paint are needed

<em><u>Solution:</u></em>

Given that, there are 3 1/3 red cups of paint for every 1 1/3 cups of blue paint

Therefore, ratio is

$Red : blue = 3\frac{1}{3} : 1\frac{1}{3}\\\\Red : blue = \frac{10}{3} : \frac{4}{3}$

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Let "x" be the cups of red paint needed

Then we get,

$\frac{10}{3} : \frac{4}{3}\\\\x : 1$

This forms a proportion

$1 \times \frac{10}{3} = \frac{4}{3} \times x\\\\x = \frac{10}{4}$

Therefore, 10/4 cups of red are needed for 1 cup of blue

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Let "x" be the cups of blue paint needed

Then, we get

$\frac{10}{3} : \frac{4}{3}\\\\1 : x$

This forms a proportion

$\frac{10}{3} \times x = \frac{4}{3} \times 1\\\\x = \frac{4}{10}$

Thus, 4/10 cups of blue are needed for 1 cup of red paint

<h3><u>For every 4 cups of red paint,___ cups of blue paint are needed</u></h3>

Let "x" be the cups of blue paint needed

Then, we get

$\frac{10}{3} : \frac{4}{3}\\\\4 : x$

This forms a proportion

$\frac{10}{3} \times x = \frac{4}{3} \times 4\\\\x = \frac{16}{10}$

Thus 16/10 cups of blue paint are needed for every 4 cups of red paint

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A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are

FrozenT [24]

Answer:

15 possible combinations

Step-by-step explanation:

Given

$Vegetables = 6$

$Selection = 2$

Required

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The question emphasizes on "selection" which means "combination".

So; To answer this question, we apply the following combination formula:

$^nC_r = \frac{n!}{(n-r)r!}$

In this case:

$n = 6$

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The formula becomes:

$^6C_2 = \frac{6!}{(6-2)!2!}$

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Answer:

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Step-by-step explanation:

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