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3 years ago

Which formula is an ionic compound? -N2 -CO2 -NO2 -NaF

Chemistry

2 answers:

Stels [109]3 years ago

8 0

Answer:

NaF

Explanation:

I took the test and i got it right.

alex41 [277]3 years ago

7 0

Answer:

NaF

Explanation:

An ionic compound is formed as a result of an ionic bond between a nonmetal ion and metal ion.
Ionic bonds are forces of attraction that occur between nonmetal atoms and metal atoms.
The metal atom loses an electron(s) to form a cation and a non-metal atom gains electron(s) to form an anion.
An ionic compound is formed as a result of the electrostatic force of attraction between the negatively charged ion(anion) and the positively charged ion(cation).
For example, sodium fluoride(NaF) is an ionic compound between Na⁺ (cation) and F⁻(anion).
Other examples of ionic compounds include NaCl, CaBr₂, KF, MgCl₂, etc.

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The concentration of a saturated BaCl2 solution is 1.75 M (mol/liter) and the concentration of a saturated Na2SO4 solution is 2.

Kitty [74]

Answer:

a) The theoretical yield is 408.45g of $BaSO_{4}$

b) Percent yield = $\frac{realyield}{408.45g}*100$

Explanation:

1. First determine the numer of moles of $BaCl_{2}$ and $Na_{2}SO_{4}$ .

Molarity is expressed as:

M= $\frac{molessolute}{Lsolution}$

- For the $BaCl_{2}$

M= $\frac{1.75molesBaCl_{2}}{1Lsolution}$

Therefore there are 1.75 moles of $BaCl_{2}$

- For the $Na_{2}SO_{4}$

M= $\frac{2.0moles[tex]Na_{2}SO_{4}$ }{1Lsolution}[/tex]

Therefore there are 2.0 moles of $Na_{2}SO_{4}$

2. Write the balanced chemical equation for the synthesis of the barium white pigment, $BaSO_{4}$ :

$BaCl_{2}+Na_{2}SO_{4}=BaSO_{4}+2NaCl$

3. Determine the limiting reagent.

To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:

- For the $BaCl_{2}$ :

$\frac{1.75}{1}=1.75$

- For the $Na_{2}SO_{4}$ :

$\frac{2.0}{1}=2.0$

As the $BaCl_{2}$ is the smalles quantity, this is the limiting reagent.

4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

$1.75molesBaCl_{2}*\frac{1molBaSO_{4}}{1molBaCl_{2}}*\frac{233.4gBaSO_{4}}{1molBaSO_{4}}=408.45gBaSO_{4}$

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:

Percent yield = $\frac{realyield}{theoreticalyield}*100$

Percent yield = $\frac{realyield}{408.45g}*100$

The real yield is the quantity of barium white pigment you obtained in the laboratory.

7 0

3 years ago

3. If you start with 8x1025 molecules of Cl, and 25 grams of KI, how many grams of KCl would

miskamm [114]

Answer:

Percent yield = 89.1%

Explanation:

Based on the equation:

Cl₂ + 2KI → 2KCl + I₂

1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl

To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:

Moles Cl₂:

8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles

Moles KI -Molar mass: 166.0028g/mol-

25g * (1mol / 166.0028g) = 0.15 moles

Here, clarely, the KI is the limiting reactant

As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:

0.15 moles * (74.5513g / mol) =

11.2g KCl

Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100

<h3>Percent yield = 89.1%</h3>

3 0

3 years ago

Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th

Gre4nikov [31]

Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

$\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M$

The given equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initially conc. 0 0 0.1576

At eqm. (x) (x) (0.1576-2x)

The expression of $K_c$ will be,

$K_c=\frac{[NO]^2}{[N_2][O_2]}$

$0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}$

By solving the term, we get:

$x=0.0742,0.0839$

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

Now we have to calculate the equilibrium concentration of NO.

Equilibrium concentration of NO = (0.1576-2x) = [0.1576-2(0.0742)] = 0.0092 M

Therefore, the equilibrium concentration of NO is, 0.0092 M.

5 0

4 years ago

PLEASE HELP!!!!! Noble gases are often described as being very stable. Give two points to explain what this means.

Leya [2.2K]

Answer:

Noble Gases are very stable because...

1) Noble Gases have a full octet

2) Low chemical reactivity

Explanation:

This means that is has 8 valence electrons so it won't need any more, so it is less likely to react with other substances.

6 0

3 years ago

What are the three characteristics properties of an acid

rjkz [21]

1) when litmus paper is dipped into a acid solution, the litmus paper turns red.
2) acid reacts with metals to produce hydrogen gas 
3) the equation of an acidic substance begins with the letter 'H' such as HCl

4 0

4 years ago