Since there is so little information given, I will assume that we are at STP and i can use the conversion factor at STP--->> 22.4 Liters= 1 mol of gas
before we use this conversion, we need to convert the grams to moles using the molar mass of the molecule.
molar mass of Cl₂= 35.5 x 2= 71.0 g/ mol
177.3 g (1 mol/ 71.0 g)= 2.50 mol Cl₂
then we use the conversion to get the volume
2.50 mol Cl₂ (22.4 Liters/ 1 mol)= 55.9 Liters
Answer:
A decrease in the total volume of the reaction vessel (T constant)
Explanation:
- Le Châtelier's principle predicts that the moles of H2 in the reaction container will increase with a decrease in the total volume of the reaction vessel.
- <em><u>According to the Le Chatelier's principle, when a chnage is a applied to a system at equilibrium, then the equilibrium will shift in a way that counteracts the effect causing it.</u></em>
- In this case, a decrease in volume means there is an increase in pressure, therefore the equilibrium will shift towards the side with the fewer number of moles of gas.
Answer:
8.76M
Explanation:
Given that
Mass from the density = 1141g
According to the given situation the computation of molarity of the solution is shown below:-
we will took HCL solution which is 1000mL
HCl = 28% by mass
So,
Mass of HCl in 1-litre solution is
Which gives the result of molar mass HCI is
= 319.48g
/mol
Now,
Molarity is
Which gives results of molarity is
= 8.76M
I can’t see the picture for some reason
Empirical formula is the simplest ratio of components making up a compound.
The percentage composition of each element has been given
therefore the mass present of each element in 100 g of compound is
B N H
mass 40.28 g 52.20 g 7.53 g
number of moles
40.28 g / 11 g/mol 52.20 g / 14 g/mol 7.53 g / 1 g/mol
= 3.662 mol = 3.729 mol = 7.53 mol
divide the number of moles by the least number of moles, that is 3.662
3.662 / 3.662 3.729 / 3.662 7.53 / 3.662
= 1.000 = 1.018 = 2.056
the ratio of the elements after rounding off to the nearest whole number is
B : N : H = 1 : 1 : 2
therefore empirical formula for the compound is B₁N₁H₂
that can be written as BNH₂
