Answer:
Although this question is not complete, I would give a general solution to this kind of problems.
If y(t) describes the position of a body with time such that
y(t) = at^(n) + bt^(m) + C
Then
V(t) = dy(t)/dt = ant^(n-1) + bmt^(m-1)
Explanation:
As an example supplies the position of a particle is given by
y(t) = 4t³- 3t² + 9
V(t) = 4x3t²- 3x2t¹
V(t) = d(t)/dt = 12t² - 6t.
Another example,
If y(t) = 15t³ - 2t² + 30t -80
V(t) = d(t)/dt = 15x3t² - 4t +30 = 45t² + 4t + 30.
Basically, in the equations above the powers of t reduces by one when computing the velocity function from y(t) by differentiation (calculating the derivative of y(t)). The constant term C (9 and 80 in the functions of y(t) in examples 1and 2 above) reduces to zero because the derivative of a constant (and ordinary number without the t attached to it) is always zero.
One last example,
y(t) = 2t^6 -3t²
V(t) = d(t)/dt = 12t^5 - 6t
I’m very sorry that you feel like this love it gets better I promise I didn’t think that it would either but it did and it will for you too
Answer:
318.5 x 10^4 Pa
Explanation:
weight of woman = m g = 65 x 9.8 = 637 N
Area of both the heels = 1 x 2 = 2 cm^2 = 2 x 10^-4 m^2
Pressure is defined as the thrust acting per unit area.
P = F / A
Where, F is the weight of the woman and A be the area of heels
P = 637 / (2 x 10^-4) = 318.5 x 10^4 Pa
Work Done = Force * Distance
This means the least work is exerted by the most distance, so the longer ones are less likely to break.
The shortest one will be the one that breaks easiest.
Answer:
To summarize, evaporation is slower, occurs only from the surface of the liquid, does not produce bubbles, and leads to cooling. Boiling is faster, can occur throughout the liquid, produces lots of bubbles, and does not result in cooling.
Explanation:
