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steposvetlana [31]
3 years ago
6

When light (or another wave) bounces back from a surface ?

Physics
1 answer:
topjm [15]3 years ago
3 0
Light bounces back due to the phenomenon called reflection. When light incidents on a plane shiny surface like mirror, it travels again in the same medium(medium from which light was incident) with no loss in energy(energy before and after reflection will remain same iff incident surface completely reflects light)
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Anwser , This Picture
egoroff_w [7]
I think CD because it was positive but also had the fastest velocity in 1 second
3 0
3 years ago
Read 2 more answers
A cosmic ray proton moving toward the Earth at 3.5x 10^7 ms experiences a magnetic force of 1.65x 10^-16 N. What is the strength
Step2247 [10]

Answer:

Magnetic field, B=4.16\times 10^{-5}\ T

Explanation:

It is given that,

Velocity of proton, v=3.5\times 10^7\ m/s

Magnetic force, F=1.65\times 10^{-16}\ N

Charge of proton, q=1.6\times 10^{-19}\ C

We need to find the strength of the magnetic field if there is a 45° angle between it and the proton's velocity. The formula for magnetic force is given by :

F=qvB\ sin\theta

B=\dfrac{F}{qv\ sin\theta}

B=\dfrac{1.65\times 10^{-16}}{1.6\times 10^{-19}\times 3.5\times 10^7\times sin(45)}

B = 0.0000416 T

B=4.16\times 10^{-5}\ T

Hence, this is the required solution.

4 0
3 years ago
A uniform disk of mass M and radius R has rotational inertia about its central axis of Idisk = 1/2 MR2. A uniform rod of mass m
expeople1 [14]

Answer:

5/6 MR²

Explanation:

In the composite object, the distance from the disk's axis to the rod's axis is R/2.  Using parallel axis theorem, the rod's new moment of inertia is:

I = 1/12 MR² + M (R/2)²

I = 1/12 MR² + 1/4 MR²

I = 1/3 MR²

The total moment of inertia is therefore:

I = 1/2 MR² + 1/3 MR²

I = 5/6 MR²

4 0
4 years ago
A ray of violet light has a wavelength of about 4.2×10−7 m. will exposure to violet light cause electrons to be emitted from ces
lesantik [10]
The wavelength of violet light is given as 4.2x10^-7 m and the speed of light is 3x10^8 m/sec

The equation relating between the frequency and the wavelength is as follows:
speed of light = wavelength x frequency

Substitute with the givens in the above equation to get the frequency of violet light as follows:
frequency = (3 x 10^8) / (4.2 x 10^-7) = 7.14285 x 10^14 Hz

The threshold frequency of cesium is <span>9.39x10^14 Hz.
Since the frequency of violet light is less than the threshold frequency of cesium, therefore, the exposure to violet light won't </span><span>cause electrons to be emitted from cesium.</span>
7 0
3 years ago
Calculate the magnitude of the linear momentum for each of the following cases
wel

Answer:

(a)p = 1.002x10^{-20}Kg.m/s

(b)p = 0.598Kg.m/s

(c)p = 94.4Kg.m/s

(d)p = 1.77x10^{29}Kg.m/s

Explanation:

The linear momentum is defined as:

p = mv  (1)

Where m is the mass and v is the velocity

<em>a.) </em><em>A proton with mass 1.67 x10^{-27} kg moving with a velocity of 6 x 10^{6} m/s. </em>

Replacing those values in equation (1) it is gotten:

p = (1.67x10^{-27}Kg)(6x10^{6}m/s)

p = 1.002x10^{-20}Kg.m/s

So, it has a linear momentum of 1.002x10^{-20}Kg.m/s

<em>b.)</em><em> A 1.6 g bullet moving with a speed of 374m/s to the right.</em>

Notice that in this case it is necessary to express the mass of the bullet in terms of kilograms:

1.6g . \frac{1Kg}{1000g} ⇒ 1.6x10^{-3}Kg

m = 1.6x10^{-3}Kg

p = (1.6x10^{-3}Kg)(374m/s)

p = 0.598Kg.m/s

<em>c.) </em><em>A 8 kg sprinter running with a velocity of 11.8 m/s. </em>

p = (8Kg)(11.8m/s)

p = 94.4Kg.m/s

<em>d.) </em><em>Earth (m=5.98x10^{24} kg) moving with an orbital speed equal to 29700 m/s.</em>

p = (5.98x10^{24}Kg)(29700m/s)

p = 1.77x10^{29}Kg.m/s

8 0
3 years ago
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