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finlep [7]
3 years ago
12

90% of people marry their 7th-grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine

comments your worst week starts now this isn't fake. apparently, if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say I love you.
Physics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

aw omg really

Explanation:

okay!

natali 33 [55]3 years ago
7 0
Those numbers are statistically incorrect.
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Hello help me pls! i need serious help
9966 [12]

Answer:c

Explanation:

7 0
3 years ago
Read 2 more answers
A particular inductor is connected to a circuit where it experiences a change in current of 0.8 amps every 0.10 sec. If the indu
nadya68 [22]

Answer:

0.4

Explanation:

Given that a particular inductor is connected to a circuit where it experiences a change in current of 0.8 amps every 0.10 sec. If the inductor has a self-inductance of 2.0 V, what is the inductance

Using the power formula

P = IV

Substitute all the parameters

P = 0.8 × 2

P = 1.6 W

But P = I^2 R

Substitute power and current

1.6 = 0.8^2 R

R = 1.6 / 0.64

R = 2.5 ohms

Inductance = reciprocal of resistance

Inductance = 1 / 2.5

Inductance = 0.4

4 0
3 years ago
The amount of friction divided by the weight of an object forms a unit less number called the
Romashka [77]

Answer:

Coefficient of friction.

Explanation:

The amount of friction divided by the weight of an object is equal to the coefficient of friction. It is a dimensional less number. It can be given by :

F=\mu N

N is normal force.

\mu = coefficient of friction

\mu=\dfrac{F}{N}

3 0
3 years ago
Gold-leaf electroscope uses
Kruka [31]
-identifies an electric charge 
-it can identify its polarity (positive or negative) if you compare it to a charge that you already know
-can identify the magnitude of a charge (how big of a charge it is)
7 0
3 years ago
how much is need to lift a load of 100n placed at a distance of 29 cm from fulcrum if effort is applied at 60cm from the fulcrum
dangina [55]

Answer:

206.8965517 n

Explanation:

First, we need to see that 60:29 is 2.078965517:1. Then we need to multiply the energy put 29 cm from the fulcrum by 2.078965517, giving us the end result of our answer.

6 0
2 years ago
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