Answer:
The answer to your question is: Ep = 14715 Joules
Explanation:
Data
mass = 50 kg
Potential energy = ?
height = 30 m
g = 9.81 m/s²
Equation
Ep = mgh
Substitution
Ep = (50)(9.81)(30)
Ep = 14715 Joules
Answer:
Explanation:
V₀ = 0 m/s
V = 41 m/s
S = 480 m
___________
a - ?
Distance traveled:
S = (V² - V₀²) / (2*a)
Acceleration :
a = (V² - V₀²) / (2*S)
a = (41² - 0²) / (2*480) = 1.75 m/s²
sorry i did not mean to answer
Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length
For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength
Put the value into the formula
We need to calculate the frequency of the tuning
Using formula of frequency
Put the value into the formula
Hence, The frequency of the tuning is 1.065 kHz
Answer:
1626.4 N
Explanation:
Given that a 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him?
The parameters to be considered are:
Distance S = 3m
Time t = 0.55s
Since the man started from rest, initial velocity u = 0
Using second equation of motion
S = Ut + 1/2at^2
3 = 1/2 × a × 0.55^2
3 = 1/2 × a × 0.3025
a = 3/ 0.15125
a = 19.83 m/s^2
Force = mass × acceleration
Force = 82 × 19.83
Force = 1626.4 N
Therefore, the force that water exerted on him is 1626.4 N
