The pair of numbers that have the greatest common factor of 3 are:
6 and 9
18 and 15
3 and 9
<h3>What is
greatest common factor?</h3>
The biggest number, which is the variable of at least two number is known as the Best Normal Element (GCF). It is the biggest number (factor) that partition them bringing about a Characteristic number. When every one of the elements of the number are found, there are not many variables which are normal in both.
The factors of 6 and 9 are:
6 ⇒ 1, 2, 3 and 6
9 ⇒ 1, 3, 9
The greatest common factor here is therefore 3.
The factors of 18 and 15 are:
18 ⇒ 1, 2, 3, 6, 9 and 18
15 ⇒ 1, 3, 5, and 15
Greatest common factor is also 3
The factors of 3 and 9 are:
3 ⇒ 1 and 3
9 ⇒ 1, 3, 9
Greatest common factor here is also 3.
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59 degrees!
because you set up your problem: 3c+2+2c-7=90
then combine all like terms: 5c-5=90
Add 5 to both sides: 5c=95
then divide both sides by 5: c=19
Plug in your answer: 3(19)+2=59
So this is integers. What you are going to do is 54 - - 34 which equals positive 20 because 54 is higher than 34 which is negative, and 54 is positive. So the answer is going to be 20$.
Answer:
![\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Ctan%28%5Ctheta%29%3D-%5Cfrac%7B%5Csqrt%7B17%7D%7D%7B8%7D)
Step-by-step explanation:
We are given that:
![\displaystyle \cos(\theta)=\frac{8}{9}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Ccos%28%5Ctheta%29%3D%5Cfrac%7B8%7D%7B9%7D)
Where θ is in QIV.
And we want to find the value of tan(θ).
Recall that cosine is the ratio of the adjacent side over the hypotenuse.
Therefore, the opposite side is:
![o=\sqrt{9^2-8^2}=\sqrt{17}](https://tex.z-dn.net/?f=o%3D%5Csqrt%7B9%5E2-8%5E2%7D%3D%5Csqrt%7B17%7D)
Next, in QIV, only cosine is positive: sine and tangent are both negative.
Tangent is the ratio of the opposite side to the adjacent. So:
![\displaystyle \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Ctan%28%5Ctheta%29%3D%5Cfrac%7B%5Ctext%7Bopposite%7D%7D%7B%5Ctext%7Badjacent%7D%7D)
Substitute. Tangent is negative in QIV. Hence:
![\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Ctan%28%5Ctheta%29%3D-%5Cfrac%7B%5Csqrt%7B17%7D%7D%7B8%7D)