Question

Rewrite the expression using only positive integer exponents.

Answer 1

Answer:

So we got:

$\left(m^{\frac{2}{3}}n^{\frac{-1}{3}}\right)^6$

$m^4\left(n^{\frac{-1}{3}}\right)^6$

More attention for $(n^{\frac{-1}{3}}\right))^6$

$n^{-2}$

$\frac{1}{n^2}$

Join:

$m^4\frac{1}{n^2}$

$\frac{1\cdot \:m^4}{n^2}\\\frac{m^4}{n^2}$

Therefore, the answer is $\frac{m^4}{n^2}$ , letter A