Answer:
Step-by-step explanation:
Hello,
<em>"Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only."</em>
We know that Kelsey is right, a polynomial of degree 3 has maximum 3 zeroes, so it means that the graph of this polynomial has maximum 3 x-intercepts.
<u>So how Ray can be right too?</u>
we need to think of y-intercept, if we add the y-intercept then Ray can be right too,
as you can see in one example below
there are 3 x-intercepts and 1 y-intercept.
This being said, Ray is not always right. For instance 
has only 1 zero (multiplicity 3) its graph has only 1 intercept in the point (0,0)
hope this helps
Answer:
DG = 30
Step-by-step explanation:
Given:
DH = 6
DE = 4
EF = 16
Required:
DG
Solution:
DG = DH + HG
DG = 6 + HG
Let's find HG
Given that HE is parallel to the third side of ∆DGF, based on the side-splitter theorem, the other two sides of ∆DGF are divided proportionally.
Therefore,
DH/HG = DE/EF
6/HG = 4/16
Cross multiply
HG*4 = 16*6
HG = 96/4
HG = 24
✔️DG = 6 + HG
DG = 6 + 24
DG = 30
Answer:
the first one
Step-by-step explanation:
In the other 2 i can see the x repeats itself meaning it isn't a function.
Im sorry i dont understand the question.. Is there another form of the question you can give me?