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saul85 [17]
3 years ago
15

Two cyclists, 50 miles apart, start riding toward each other at the same time. One cycles 4 times as fast as the other, and they

meet after 2 hours of riding. a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r r to represent the speed of the slower cyclist?
Physics
1 answer:
Bond [772]3 years ago
3 0

Answer:speed of slower cyclist is 5 mph

Explanation:

Given

Distance between two cyclist is 50 miles

One cycle is 4 times fast as other

Speed of slower cyclist is r miles per hour

speed of faster cyclist is 4 r

they meet after t=2 hr

Distance traveled by fast cyclist is x=2\times 4r

Distance traveled by slower cyclist is y=2\times r

x+y=50

2\times 4r+2\times r=50

8r+2r=50

10r=50

r=5 mph

4 r=20 mph

speed of slower cyclist is 5 miles per hour

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A skydiver jumps out of a hovering helicopter. A few seconds later, another diver jumps out, so they both fall along the same ve
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Answer:

distance difference would a) increase

speed difference would f) stay the same

Explanation:

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Their difference in distance are therefore:

\Delta s = s_1 - s_2 = g(t + \Delta t)^2/2 - gt^2/2

\Delta s = g/2((t + \Delta t)^2 - t^2)

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So as time progress t increases, Δs would also increases, their distance becomes wider with time.

Similarly for their velocity difference

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Since g and Δt both are constant, Δv would also remain constant, their difference in velocity remain the same.

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