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2 years ago

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Two cyclists, 50 miles apart, start riding toward each other at the same time. One cycles 4 times as fast as the other, and they

meet after 2 hours of riding. a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r r to represent the speed of the slower cyclist?

1 answer:

Bond [772]2 years ago

3 0

Answer:speed of slower cyclist is 5 mph

Explanation:

Given

Distance between two cyclist is 50 miles

One cycle is 4 times fast as other

Speed of slower cyclist is r miles per hour

speed of faster cyclist is 4 r

they meet after t=2 hr

Distance traveled by fast cyclist is $x=2\times 4r$

Distance traveled by slower cyclist is $y=2\times r$

$x+y=50$

$2\times 4r+2\times r=50$

$8r+2r=50$

$10r=50$

$r=5 mph$

$4 r=20 mph$

speed of slower cyclist is 5 miles per hour

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HELP When the forces are applied in the same direction, how do you determine net force?

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Answer:

Explanation:

If two forces act on an object in the same direction, the net force is equal to the sum of the two forces.

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3 years ago

A tennis ball with a velocity of +10.0 m/s to the right is thrown perpendicularly at a wall. After striking the wall, the ball r

netineya [11]

Answer:

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3 years ago

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent

azamat

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

<em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

$L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}$

for first mode: n = 1

$\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm$

for second mode: n = 2

$\lambda = \frac{2L}{2} = L = 100 \ cm$

For the third mode: n = 3

$\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm$

For fourth mode: n = 4

$\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50 \ cm$

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

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2 years ago

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2 years ago

Read 2 more answers

A solid sphere has a radius of 0.200 m and a mass of 150.0 kg. how much work is required to get the sphere rolling with an angul

Allisa [31]

Here in this case we can use work energy theorem

As per work energy theorem

Work done by all forces = Change in kinetic Energy of the object

Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.

Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy

$KE = \frac{1}{2}Iw^2 +\frac{1}{2} mv^2$

also we know that

$I = \frac{2}{5}mR^2$

$w= \frac{v}{R}$

Now kinetic energy is given by

$KE = \frac{1}{2}(\frac{2}{5}mR^2)w^2 +\frac{1}{2} m(Rw)^2$

$KE = \frac{1}{5}mR^2w^2 +\frac{1}{2} mR^2w^2$

$KE = \frac{7}{10}mR^2w^2$

$KE = \frac{7}{10}*150*(0.200)^2(50)^2$

$KE = 10500 J$

Now by work energy theorem

Work done = 10500 - 0 = 10500 J

So in the above case work done on sphere is 10500 J

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2 years ago