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saul85 [17]
3 years ago
15

Two cyclists, 50 miles apart, start riding toward each other at the same time. One cycles 4 times as fast as the other, and they

meet after 2 hours of riding. a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r r to represent the speed of the slower cyclist?
Physics
1 answer:
Bond [772]3 years ago
3 0

Answer:speed of slower cyclist is 5 mph

Explanation:

Given

Distance between two cyclist is 50 miles

One cycle is 4 times fast as other

Speed of slower cyclist is r miles per hour

speed of faster cyclist is 4 r

they meet after t=2 hr

Distance traveled by fast cyclist is x=2\times 4r

Distance traveled by slower cyclist is y=2\times r

x+y=50

2\times 4r+2\times r=50

8r+2r=50

10r=50

r=5 mph

4 r=20 mph

speed of slower cyclist is 5 miles per hour

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Answer:

Im pretty sure it's C

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V = 36 cm^{2} x 10 cm

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The seat belt is applying a force in the opposite direction.

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34)You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then
velikii [3]

Answer:

F_H_n=230.04 N

The Required  horizontal force is 230.04N

Explanation:

Since the velocity is constant so acceleration is zero; a=0

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F_H=(1.42m*g*.81u)          Eq (2)

Divide Eq(2) and Eq (1)

\frac{F_H_n}{200}=\frac{1.42m*g*0.81u}{m*g*u}\\F_H_n=1.42*0.81*200\\F_H_n=230.04 N

The Required  horizontal force is 230.04N

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