Answer:
V=4.7m/s
Explanations:
Let Ma mass of cat A=7kg
Va velocity of cat A=7m/s
Mb mass of cat b=6.1kg
VB velocity of cat b=2m/s
From conservation of linear momentum
MaVa+MbVb=(Ma+Mb)V
7*7+6.1*2=(7+6.1)V
61.2=13.1V
V=4.7m/s
This can be solve using the formula P = I^2 * Rwhere P is the powerI is the CurrentR is the resistanceP = I^2 * R
1/4 Watt = I^2 * 100 ohm solve for II^2 = 1/400 I = 0.05 amps then using the formula to solve for the voltage:V = I * RV = 0.05 amps * 100 ohms V = 5 volts
Answer:
g = 11.2 m/s²
Explanation:
First, we will calculate the time period of the pendulum:
where,
T = Time period = ?
t = time taken = 135 s
n = no. of swings in given time = 98
Therefore,
T = 1.38 s
Now, we utilize the second formula for the time period of the simple pendulum, given as follows:
where,
l = length of pendulum = 54 cm = 0.54 m
g = acceleration due to gravity on the planet = ?
Therefore,
<u>g = 11.2 m/s²</u>
Answer:
One would need to know how far apart the towns are:
T = SA / 40 time it takes for first cyclist to travel S1
T = SB / 60 time it takes for cyclist B to travel distance S2
SA + SB = S the distance between the towns
SB = 60 / 40 SA = 1.5 SA
SA + 1.5 SA = S
S = 2.5 SA where cyclist travels distance SA
The time will depend on the separation of the towns.
