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RSB [31]
3 years ago
10

A chemist has a 2.0 M solution of copper (II) sulfate. Is he takes 400 mL of this solution and dilutes it with 1200 mL of water,

which of the following would be the most accurate calculation of the molarity of the new solution?
Chemistry
1 answer:
Ksenya-84 [330]3 years ago
4 0

0.66 M is the accurate molarity of the new solution of volume of 1200 ml.

Explanation:

Data given:

molarity of copper(II) sulphate, Mconc.= 2M

volume of 2M solution taken Vconc. = 400 ml

volume taken for dilution, Vdilute = 1200 ml

molarity of the diluted solution, Mdilute =?

We will use the formula for dilution as

Mconc Vconc = Mdilute x V dilute  (conc is concentrated)

putting the values in the equation:

2 x 400 = Mdilute x 1200

Mdilute = \frac{800}{1200}

   Mdilute  = 0.66 M

When the solution is diluted to the volume of 1200 ml its molarity changes to 0.66 M.

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Write a balanced nuclear equation for the following: The nuclide astatine-218 undergoes alpha emission to give bismuth-214
galina1969 [7]

Answer:

^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He

Explanation:

Hello there!

In this case, since the radioactive reaction for the alpha emission of astatine-218 to bismith-214 involve the release of a helium atom as shown below:

^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He

Whereas the atomic number decreases by 2 and the mass number by 4 in agreement to the release of the Helium atom.

Regards!

7 0
3 years ago
Which one of the following equations represents the net ionic equation for the reaction between aqueous potassium chloride and a
Nana76 [90]
<h3>Answer:</h3>

Ag⁺(aq) +Cl⁻(aq) → AgCl(s)

<h3>Explanation:</h3>

The questions requires we write the net ionic equation for the reaction between aqueous potassium chloride and aqueous silver nitrate.

<h3>Step 1: Writing a balanced equation for the reaction.</h3>
  • The balanced equation for the reaction between aqueous potassium chloride and aqueous silver nitrate will be given by;

KCl(aq) + AgNO₃(aq) → KNO₃(aq) +AgCl(s)

  • AgCl is the precipitate formed by the reaction.
<h3>Step 2: Write the complete ionic equation.</h3>
  • The complete ionic equation for the reaction is given by showing all the ions involved in the reaction.

K⁺(aq)Cl⁻(aq) + Ag⁺(aq)NO₃⁻(aq) → K⁺(aq)NO₃⁻(aq) +AgCl(s)

  • Only ionic compounds are split into ions.
<h3>Step 3: Write the net ionic equation for the reaction.</h3>
  • The net ionic equation for a reactions only the ions that fully participated in the reaction and omits the ions that did not participate in the reaction.
  • The ions that are not involved directly in the reaction are known as spectator ions and are not included while writing net ionic equation.

Ag⁺(aq) +Cl⁻(aq) → AgCl(s)

4 0
3 years ago
A mixture of two compounds, A and B, was separated by extraction. After the compounds were dried, their masses were found to be:
Arlecino [84]

Answer:

The percent recovery from re crystallization for both compounds A and B is 69.745 and 81.44 % respectively.

Explanation:

Mass of compound A in a mixture  = 119 mg

Mass of compound A after re-crystallization = 83 mg

Percent recovery from re-crystallization :

\frac{\text{Mass after re-crystallization}}{\text{Mass before re-crystallization}}\times 100

Percent recovery of compound A:

\frac{83 mg}{119 mg}\times 100=69.74\%

Mass of compound B in a mixture  = 97 mg

Mass of compound B after re-crystallization = 79 mg

Percent recovery of compound B:

\frac{79 mg}{97 mg}\times 100=81.44\%

3 0
3 years ago
When work is done on an object, the amount of ________ it has changes.
arsen [322]
Hey there!

When work is done on an object, the amount of energy it has changes.

Hope this helps!

~Autumly
3 0
3 years ago
A sample of nitrogen gas has a volume of 478 cm3 and a pressure of 104.1 kPa. What volume would the gas occupy at 88.2 kPa if th
nadezda [96]

<span>1.    </span>To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

V2 = P1 x V1 / P2

 V2 = 104.1 x 478 / 88.2

<span> V2 =564.17 cm^3</span>

6 0
3 years ago
Read 2 more answers
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