Determine the number of formula units of Cr(ClO2)3 and moles of Oxygen contained in 6.85 moles of Cr(ClO2)3

Chemistry

1 answer:

Advocard [28]3 years ago

4 0

The formula units of Cr(ClO2)3 that are in 6.85 moles of Cr(Clo203 is <u>4.1237 x10^24 formula units</u>

calculation

the formula units are calculated using of Avogadro's law constant

that is according to Avogadro's law 1 mole = 6.02 x10 ^23 formula units

6.85 moles= ? formula units

by cross multiplication.

= ( 6.85 moles x 6.02 x10^23 formula units ) / 1 mole = <u>4.1237 x 10 ^24 formula units</u>

<h3>The moles of Oxygen contained in 6.85 moles of cr(ClO2)3 is <em><u>41.1 moles</u></em></h3>

<em><u> </u></em><u><em>calculation</em></u>

<em>moles of oxygen = number of oxygen atom in Cr(ClO2)3 x 6.85(moles of Cr(ClO2)3</em>

calculate the number of oxygen atoms that are in Cr(ClO2)3

that is 2 x 3 = 6 atoms of Oxygen.

moles is therefore = 6 x 6.85 moles= 41.1 moles

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