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Bingel [31]
3 years ago
14

Determine the number of formula units of Cr(ClO2)3 and moles of Oxygen contained in 6.85 moles of Cr(ClO2)3

Chemistry
1 answer:
Advocard [28]3 years ago
4 0

The formula  units  of Cr(ClO2)3  that  are in 6.85  moles of Cr(Clo203  is  <u>4.1237 x10^24  formula units</u>


 calculation

  the formula units are  calculated using of Avogadro's  law  constant

that is   according  to Avogadro's law   1  mole = 6.02 x10 ^23  formula units

                                                             6.85 moles= ?  formula units

by  cross  multiplication.

 = ( 6.85 moles   x 6.02  x10^23  formula units )  / 1 mole  = <u>4.1237  x 10 ^24  formula units</u>



<h3>The moles of  Oxygen  contained  in 6.85  moles of cr(ClO2)3  is    <em><u>41.1  moles</u></em></h3>

<em><u>  </u></em><u><em>calculation</em></u>

<em>moles   of  oxygen = number of oxygen atom in  Cr(ClO2)3  x   6.85(moles of  Cr(ClO2)3</em>

calculate the number of   oxygen atoms that  are in Cr(ClO2)3

that is  2 x 3 = 6 atoms of Oxygen.

moles is therefore =  6  x 6.85 moles= 41.1 moles

<h3></h3>

 

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