All categories

2 years ago

Determine the number of formula units of Cr(ClO2)3 and moles of Oxygen contained in 6.85 moles of Cr(ClO2)3

Chemistry

1 answer:

Advocard [28]2 years ago

4 0

The formula units of Cr(ClO2)3 that are in 6.85 moles of Cr(Clo203 is <u>4.1237 x10^24 formula units</u>

calculation

the formula units are calculated using of Avogadro's law constant

that is according to Avogadro's law 1 mole = 6.02 x10 ^23 formula units

6.85 moles= ? formula units

by cross multiplication.

= ( 6.85 moles x 6.02 x10^23 formula units ) / 1 mole = <u>4.1237 x 10 ^24 formula units</u>

<h3>The moles of Oxygen contained in 6.85 moles of cr(ClO2)3 is <em><u>41.1 moles</u></em></h3>

<em><u> </u></em><u><em>calculation</em></u>

<em>moles of oxygen = number of oxygen atom in Cr(ClO2)3 x 6.85(moles of Cr(ClO2)3</em>

calculate the number of oxygen atoms that are in Cr(ClO2)3

that is 2 x 3 = 6 atoms of Oxygen.

moles is therefore = 6 x 6.85 moles= 41.1 moles

You might be interested in

Heat transmits readily through this

Oksi-84 [34.3K]

Can you be more specific?

...Diamond is the best conductor of heat, but heat also transmits readily through many other substances. Do you have multiple choice?

8 0

3 years ago

Cis-3-tert-Butylcyclohexanol has the tert-butyl group in the equatorial position and the alcohol in the ________ position.

Anni [7]

Answer:

Axial

Explanation:

In the most stable conformation of Cis-3-tert-Butylcyclohexanol, the tert-butyl group is at equatorial position and the alcohol group is in the axial position.

If the tert-butyl group is placed in equatorial position, repulsions are minimized. The bulkier the group, the greater the energy difference between the axial and equatorial conformers. Hence for a ring having a bulky substituent, such bulky substituent is better placed in the equatorial position.

The energy difference between the conformers of Cis-3-tert-Butylcyclohexanol is so high that the compound is almost "frozen" in a conformation where the tert-butyl groups are equatorial and the -OH groups are axial. This conformer is more stable by 24 KJ/mol.

8 0

3 years ago

~lever

aleksandr82 [10.1K]

Block and tackle d is the best answer

3 0

3 years ago

How much energy is needed to heat 2.00g of carbon from 50.0 degrees Celsius to 80.0 degrees Celsius If carbon specific heat capa

Sedaia [141]

Answer:

huhuhuhuhuhuhuhhihihihuhuhuhjgjfngnvnffv 42.6j

Explanation:

7 0

3 years ago

Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di

pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

$Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)$

Moles of calcium nitrate = $\frac{31.3 g}{164 g/mol}=0.1908 mol$

Moles of ammonium fluoride = $\frac{38.7 g}{37 g/mol}=1.046 mol$

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

$\frac{1}{2}\times 1.046 mol=0.523 mol$ calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

$\frac{2}{1}\times 0.1908 mol=0.3816 mol$ of dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant.

8 0

3 years ago