<h3>
Answer: 102.5 degrees</h3>
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Explanation:
If angle A is 43 degrees, then minor arc BC is 2*43 = 86 degrees according to the inscribed angle theorem. The central angle is twice that of the inscribed angle. Both of these angles subtend the same minor arc.
When I say "minor arc BC", I mean that we go from B to C along the shortest path. Any minor arc is always less than 180 degrees.
Since minor arc AB is 69 degrees, and minor arc BC is 86 degrees, this means arc ABC is arcAB+arcBC = 69+86 = 155 degrees
Let's say point D is some point on the circle that isn't between A and B, and it's not between B and C either. Refer to the diagram below. The diagram is to scale. The diagram your teacher provided is not to scale because arc ABC is way too big (it appears to be over 180 degrees). Hopefully the diagram below gives you a better sense of what's going on.
Because arc ABC = 155 degrees, this means the remaining part of the circle, arc ADC, is 360-(arc ABC) = 360-155 = 205 degrees
Inscribed angle B subtends arc ADC. So we'll use the inscribed angle theorem again, but this time go in reverse from before. We'll cut that 205 degree angle in half to get 205/2 = 102.5 degrees which is the measure of angle B. This value is exact. In this case, we don't need to apply any rounding.
Answer:
Step-by-step explanation:
1 is x and 0 is y while 6 is x and -3 is y and 6,-3 is the 2nd graph
<h3>
Answer:</h3>
818.4 in²
<h3>
Step-by-step explanation:</h3>
The area of a circular sector is given by ...
... A = (1/2)r²·θ . . . . . θ in radians
The area of the isosceles triangle with apex angle 150° is given by ...
... A = (1/2)r²·sin(θ)
Then the area of the shaded segment is ...
... A = (1/2)r²·(θ - sin(θ))
... A = (1/2)·(27.8 in)²(5π/6 -sin(5π/6)) ≈ 818.4 in²
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If you (erroneously) use 3.14 for π, you get 817.9 in². Some answer keys expect you to use that value, even though it does not have sufficient accuracy for this problem.
Answer:
False
Step-by-step explanation:
A composite figure would be any irregular shapes and can be made up of multiple shapes
- Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept.
If two lines are perpendicular, then they will have slopes that are <u>negative reciprocals</u> to each other. An example of negative reciprocals are 2 and -1/2
<h2>6.</h2>
Now with line 2, I have to convert it to slope intercept form. Firstly, subtract 2x on both sides of the equation: 
Next, divide both sides by -5 and your slope-intercept form is 
Now since 2/5 is <em>not</em> the negative reciprocal of -2/5, <u>these lines are not perpendicular.</u>
<h2>7.</h2>
It's pretty much the same process; convert to slope-intercept and determine if negative reciprocal. This time I'll brush through them:
Now since 2 <em>is</em> the negative reciprocal of -1/2, <u>these lines are perpendicular.</u>
