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LenaWriter [7]
3 years ago
7

In general, what is the effect if increased temperature on the solubility of a gas

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Increased temperature causes an increase in kinetic energy. The higher kinetic energy causes more motion in the gas molecules which break intermolecular bonds and escape from solution.

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A typical air sample in the lungs contains oxygen at 100 mmhg, nitrogen at 573 mmhg, carbon dioxide at 40 mmhg, and water vapor
nikdorinn [45]
  it  is  called the  partial pressure   because    it  is    pressure  that   is  exerted by  each gas in  a mixture of  gases if it occupy  the same   volume  of  it  own.  the  the partial pressure  of oxygen  in the air sample above is  100 mm hg, that of  carbon dioxide is 40 mmhg, for   water vapor  47 mmhg. and that of  nitrogen  is 573 mmhg
4 0
3 years ago
What is the lower concentration limit (vol%) at which a mixture of ethanol in air can explode?
liubo4ka [24]

Answer:

Lower explosive limit (LEL) of ethanol = 3.3%

Explanation:

In the case of alcohol, ethanol presents certain fire hazards. Its momentary flash point is 55ºF (12.9ºC), while the momentary flash point of gasoline is -45ºF (-42.8ºC), and the E85 mixture ranges between -20ºF and -4ºF (between -28 , 9ºC and -20ºC), and has a wider range of flammability limits than gasoline. For emergency response teams, this implies that during a release of the typical ethanol / gasoline mixture, the fuel can be expected to behave like gasoline: It is heavier than air - as we mentioned earlier - and can produce vapors and form flammable mixtures in the air, under most environmental conditions.

General properties and comparison with other inflambles products:

Flash point momentary Gasoline = -45 ° F

<u>Ethanol</u> = 55 ° F

E 85 = between -20º and -4º F

<u>Flammability limits </u>

Lower explosive limit (LEL) of ethanol = 3.3%

Upper Explosive Limit (UEL) = 19%

Lower explosive limit (LEL) of the mixture E 85 = 1.4%

Upper Explosive Limit (UEL) 85 = 19%

Lower explosive limit (LEL) of gasoline = 1.4%

Upper Explosive Limit (UEL) = 7.6%

They have a wider range than gasoline

4 0
3 years ago
_______ is the amount of heat necessary to raise the temperature of 1 gram of a substance by 1 degree Kelvin. A. A calorie B. En
Maksim231197 [3]
<h2>The required option d) "specific heat" is correct.</h2>

Explanation:

  • To raise the temperature of any substance or material of certain mass to respective temperature it requires some amount of heat.
  • Specific heat is the amount of heat necessary to raise the temperature of the substance of 1 gram to 1 Kelvin.
  • It is the amount of heat which is required to raise the temperature per unit mass to per unit temperature.
  • Thus, the required "option d) specific heat" is correct.
5 0
3 years ago
A solution is made by dissolving
nikklg [1K]

Answer:

THE MOLARITY IS 2.22 MOL/DM3

Explanation:

The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water

Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol

Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;

37.5 g of Na2S = 217 g of water

( 37.5 * 1000 / 217 ) g = 1000 g of water

So, 172.81 g/dm3 of the solution

So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass

Molarity = 172.81 g/dm3 / 78 g/mol

Molarity = 2.22 mol/dm3

The molarity of the solution is 2.22 mol/dm3

4 0
4 years ago
Create the Lewis structure of CF4. NOTE: do only the step asked for in each part and then click Check–don't work ahead to solve
Naya [18.7K]

To create the Lewis structure we need to take into account the octet rule: atoms tend to gain, lose or share electrons to complete their valence shell with 8 electrons.

C belongs to Group 4A in the periodic table so it has 4 valence electrons. It needs to share 4 pairs of electrons to complete the octet.

F belongs to Group 7A in the periodic table so it has 7 valence electrons. Each F needs to share 1 pair of electrons to complete the octet.

As a consequence, in CF₄, C will form a single bond with each F and all the octets will be complete.

5 0
3 years ago
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