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grin007 [14]
3 years ago
10

How can we remove the hardness of water by boiling?​

Chemistry
1 answer:
pantera1 [17]3 years ago
5 0

Heat makes it softer

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The names and chemical formulae of some chemical compounds are written in the first two columns of the table below. Each compoun
charle [14.2K]

Answer:

See below  

Explanation:

<u>          Name         </u>  <u>Formula </u>      <u>       Major species     </u> <u>  </u>        

Zinc iodide              ZnI₂            H₂O(ℓ),  I⁻(aq), Zn²⁺(aq),  

Nitrogen(I) oxide     N₂O           H₂O(ℓ),  N₂O(aq)

Sodium nitrite         NaNO₂      H₂O(ℓ),  Na⁺(aq), NO₂⁻(aq)

Glucose                   C₆H₁₂O₆    H₂O(ℓ),  C₆H₁₂O₆(aq)

Nickel(II) iodide       NiI₂            H₂O(ℓ),  I⁻(aq), Ni²⁺(aq)

  • Glucose and nitrogen(I) oxide are covalent compounds. They do not dissociate in solution.
  • The compounds containing metals are ionic. They produce ions in solution.
  • ZnI₂ and NiI₂ produce twice as many iodide ions as metal ions.
6 0
3 years ago
How much does the mass of 12.65-g sample of copper(II) nitrate hexahydrate decrease when heated?
garik1379 [7]
There is 103 percent of water in hydrate
4 0
2 years ago
Using aluminium as an example, describe the key properties of p-block metals.
olga nikolaevna [1]

Answer:

P-block metals have classic metal characteristics like they are shiny, they are good conductors of heat and electricity, and they lose electrons easily. These metals have high melting points and readily react with nonmetals to form ionic compounds.

Explanation:

6 0
2 years ago
Read 2 more answers
What element has an atomic mass 4?
Daniel [21]

Answer:

Helium has atomic mass  4.002602.

So the answer to yr question is helium.

4 0
3 years ago
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At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
wariber [46]

Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

x_i = 0.9718

x_i+x_2=1

x_2 = 1- x_i

x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

3 0
3 years ago
Read 2 more answers
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