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il63 [147K]
3 years ago
6

A rectangular plate is supported by three cables as shown. knowing that the tension in cable ab is 408 n, determine the componen

ts of the force exerted on the plate at
b.

Physics
1 answer:
Sholpan [36]3 years ago
4 0

Answer:

  (192i +288j -216k) N

Explanation:

The un-normalized vector BA is ...

  320i +480j -360k

Then the normalized vector is ...

  (8i +12j -9k)/√(8² +12² +(-9)²) = (8/17)i +(12/17)j -(9/17)k

The cable tension multiplies this to give the components of cable tension:

  (408 N)((8/17)i +(12/17)j -(9/17)k) = (192i +288j -216k) N

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According to Newton's<br> Ist law, what will an<br> object in motion tend<br> to do?
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Answer:

According to <em>Newton's first law of motion:</em>

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Light has been measured as traveling at 3×108 m/s in a vacuum. Which of the following also travels at the speed of light, and wh
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4 0
2 years ago
The position of a particle as it moves along an y axis is given by y = (2.0cm)sin(πt/4), with t in second and y in centimeters.
irina [24]

Part a)

At t = 0  the position of the object is given as

x = 0

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x = 2 sin(\pi/2) = 2cm

so displacement of the object is given as

d = 2 - 0 = 2cm

so average speed is given as

v_{avg} = \frac{2}{2} = 1 cm/s

Part b)

instantaneous speed is given by

v = \frac{dy}{dt}

v = 2cos(\pi t/4 ) * \frac{\pi}{4}

now at t= 0

v = \frac{\pi}{2} cm/s

at t = 1

v = 2 cos(\pi/4) * \frac{\pi}{4}

v = \frac{\pi}{2\sqrt2}

at t = 2

v = 0

Part c)

Average acceleration is given as

a_{avg} = \frac{v_f - v_i}{t}

a_{avg} = \frac{0 - \frac{\pi}{2}}{2}

a = -\frac{\pi}{4} cm/s^2

Part d)

Now for instantaneous acceleration

As we know that

a =- \omega^2 y

at t = 0

a = -\frac{\pi^2}{16} * 0 = 0 cm/s^2

at t = 1

y = \sqrt2 cm

now we have

a = -\frac{\pi^2}{16}*\sqrt2

At t = 2 we have

y = 2 cm

a = -\frac{\pi^2}{16}*2

a = -\frac{\pi^2}{8}

<em>so above is the instantaneous accelerations</em>

7 0
3 years ago
A 1000-kg car moving at 10 m/s brakes to a stop in 5 s. the average braking force is
Marina86 [1]
To calcculate the braking force of the car moving, we use Newton's second law of motion which relates the acceleration and the force of an object moving. The force of an object moving is directly proportional to its acceleration and the proportionality constant is the mass of the object. It is expressed as:

Force = ma

Acceleration is the rate of change of the velocity of a moving object. We calculate acceleration from the velocity and the time given above.

a = (10 m/s) / 5 s = 2 m/s^2

So,
Force = ma
Force = 1000 kg ( 2 m/s^2 )
Force = 2000 kg m/s^2 or 2000 N
4 0
3 years ago
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