A rectangular plate is supported by three cables as shown. knowing that the tension in cable ab is 408 n, determine the componen
ts of the force exerted on the plate at
b.
b.
1 answer:
Answer:
(192i +288j -216k) N
Explanation:
The un-normalized vector BA is ...
320i +480j -360k
Then the normalized vector is ...
(8i +12j -9k)/√(8² +12² +(-9)²) = (8/17)i +(12/17)j -(9/17)k
The cable tension multiplies this to give the components of cable tension:
(408 N)((8/17)i +(12/17)j -(9/17)k) = (192i +288j -216k) N
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Answer:
The value of the effective (rms) voltage of the applied source in the circuit is 132 V
Explanation:
Given;
effective (rms) voltage of the resistor, = 65 V
effective (rms) voltage of the inductor, = 140 V
effective (rms) voltage of the capacitor, = 80 V
Determine the value of the effective (rms) voltage of the applied source in the circuit;
Therefore, the value of the effective (rms) voltage of the applied source in the circuit is 132 V.
1) Gravitational potential energy: 73 500 J
2) Kinetic energy: 135 000 J
3) Mechanical energy: 208 500 J
Explanation:
1)
The gravitational potential energy of an object is the energy possessed by the object due to its position in the Earth's gravitational field, and it is given by
where
m is the mass of the object
is the acceleration of gravity
h is the height of the object relative to the ground
For the skydiver in this problem,
m = 75 kg is his mass
h = 100 m is his height above the Earth
Substituting, we find
2)
The kinetic energy of a body is the energy due to its motion, and it is given by
where
m is the mass of the body
v is its speed
For the skydiver in this problem,
m = 75 kg is his mass
v = 60 m/s is his speed
Substituting, we find the kinetic energy
3)
The mechanical energy of an object is the sum of the gravitational potential energy and the kinetic energy of the object:
where
U is the gravitational potential energy
K is the kinetic energy
For the skydiver in this problem,
U = 73,500 J is the gravitational potential energy
K = 135,000 J is the kinetic energy
Substituting, we find
Learn more about potential energy and kinetic energy:
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