A rectangular plate is supported by three cables as shown. knowing that the tension in cable ab is 408 n, determine the componen
ts of the force exerted on the plate at
b.
b.
1 answer:
Answer:
(192i +288j -216k) N
Explanation:
The un-normalized vector BA is ...
320i +480j -360k
Then the normalized vector is ...
(8i +12j -9k)/√(8² +12² +(-9)²) = (8/17)i +(12/17)j -(9/17)k
The cable tension multiplies this to give the components of cable tension:
(408 N)((8/17)i +(12/17)j -(9/17)k) = (192i +288j -216k) N
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Answer:
The final position is (2, 7)m
Explanation:
When we work with coordinate pairs, the addition works as:
(a, b) + (c, d) = (a + c, b + d)
So, for example, if we start at (a, b), and we have a displacement d = (1, 1)
we just need to solve:
(a, b) + (1, 1) = (a + 1, b + 1)
Now, in this case, we start at (4, 4)m
first, we have d1 = (2, -3) m
After this displacement, the position is:
(4, 4)m + (2, -3)m = (4 + 2, 4 - 3)m = (6, 1)m
Now we have a displacement d2 = (-5, 0) m
After this, the position is:
(6, 1)m + (-5, 0)m = (6 -5, 1 + 0)m = (1, 1)m
After this, we have the final displacement d3 = (1, 6) m, so the final position will be:
(1, 1)m + (1, 6)m = (1 + 1, 1 + 6)m = (2, 7)m
Below you can see a rough sketch of the path that the student take, where he/she starts at point A.
