During the first 50 s a truck traveled at constant speed of 25 m/s. Find the distance that it is traveled.

Two astronauts of mass 100 kg are 2 m apart in outer space. What is the

fredd [130]

The force of gravity between the astronauts is $1.67\cdot 10^{-7}N$

Explanation:

The magnitude of the gravitational force between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where :

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

$m_1, m_2$ are the masses of the two objects

r is the separation between them

In this problem, we have two astronauts, whose masses are:

$m_1 = 100 kg\\m_2 = 100 kg$

While the separation between the astronauts is

r = 2 m

Substituting into the equation, we can find the gravitational force between the two astronauts:

$F=\frac{(6.67\cdot 10^{-11})(100)(100)}{2^2}=1.67\cdot 10^{-7}N$

Learn more about gravitational force:

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4 0

3 years ago

Read 2 more answers

Consider a spherical capacitor with radius of the inner conducting sphere a and the outer shell b. The outer shell is grounded (

AleksAgata [21]

Answer:

Explanation:

The application of Gauss's law is used in the derivation as shown with detailed step by step in the attached file.

The potential difference on this spherical capacitor is ΔV = Va - Vb = kQ/a - kQ/b = kQ(1/a - 1/b)

6 0

3 years ago

Describe The energy conversions that occur when coal is formed, and then burned to produce thermal energy.

svlad2 [7]

Answer:

When energy contained in coal is turned into heat, and then into electrical energy. As boiling water heated by the burning coal is cooled, steam forges from these cone-shaped cooling towers.

8 0

3 years ago

Notice that all the initial spring potential energy was transformed into gravitational potential energy. If you compressed the s

Nostrana [21]

<u><em>The question doesn't provide enough data to be solved, but I'm assuming some magnitudes to help you to solve your own problem</em></u>

Answer:

<em>The maximum height is 0.10 meters</em>

Explanation:

<u>Energy Transformation</u>

It's referred to as the change of one energy from one form to another or others. If we compress a spring and then release it with an object being launched on top of it, all the spring (elastic) potential energy is transformed into kinetic and gravitational energies. When the object stops in the air, all the initial energy is now gravitational potential energy.

If a spring of constant K is compressed a distance x, its potential energy is

$\displaystyle P_E=\frac{Kx^2}{2}$

When the launched object (mass m) reaches its max height h, all that energy is now gravitational, which is computed as

$U=mgh$

We have then,

$U=P_E$

$\displaystyle mgh=\frac{Kx^2}{2}$

Solving for h

$\displaystyle h=\frac{Kx^2}{2mg}$

We have little data to work on the problem, so we'll assume some values to answer the question and help to solve the problem at hand

Let's say: x=0.2 m (given), K=100 N/m, m=2 kg

Computing the maximum height

$\displaystyle h=\frac{(100)0.2^2}{2(2)(9.8)}$

$\displaystyle h=\frac{4}{39.2}=0,10\ m$

The maximum height is 0.10 meters

8 0

3 years ago

IM A plastic sphere floats in water with 50.0% of its volume submerged. This same sphere floats in glycerin with 40.0 \% of its

arsen [322]

Density of glycerin is 5/4 times water density.

Density of the sphere is 1/2 times water density.

<h3>How to find the density of sphere floats and glycerin?</h3>

Density is defined as the ratio of mass to volume, that is density is the amount of mass per unit of volume.

A substance's density exist defined as its mass per unit of volume. Density is most frequently represented by the symbol, however Latin letter D may also be utilized. If the mass or volume of an object is altered, the density of the thing may also change. Water, for example, has a specific density. An object will sink if its density exists greater than that of water; it will float if its density is lower.

Since a plastic sphere floats in water with 50% of its volume submerged.

So, the Density of the sphere = 1/2× water density

Since the same sphere floats in glycerin with 40% of its volume submerged.

So, the Density of the sphere = 4/100 × Glycerin density

= 2/5 × Glycerin density

Density of Glycerin = 5/2 of sphere density

Density of glycerin = 5/2 × 1/2 × water density

Density of glycerin = 5/4 × water density

To learn more about the volume of sphere floats refer to:

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6 0

1 year ago