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4 years ago

Which change will always result in an increase in the gravitational force between two objects?

Physics

2 answers:

lora16 [44]4 years ago

8 0

The gravitational force of two objects, by definition, is given by:

$F = G * (\frac{m1m2}{d ^ 2})$

Where,

G: gravitational constant

m1: mass of object number 1.

m2: mass of object number 2.

d: distance between both objects.

Therefore, according to the given equation, a change that always results in an increase in gravitational force is:

Increase in the mass of the objects and decrease in the distance between them.

Answer:

A change that will always result in an increase in the gravitational force between two objects is:

Increase in the mass of the objects and decrease in the distance between them.

Vadim26 [7]4 years ago

6 0

The change that will always result in an increase in the gravitational force between two objects is increasing the masses of the objects and decreasing the distance between the objects

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Friction provides the force needed for a car to travel around a flat, circular race track. What is the maximum speed at which a

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Answer:

Maximum speed of the car is 17.37 m/s.

Explanation:

Given that,

Radius of the circular track, r = 79 m

The coefficient of friction, $\mu=0.39$

To find,

The maximum speed of car.

Solution,

Let v is the maximum speed of the car at which it can safely travel. It can be calculated by balancing the centripetal force and the gravitational force acting on it as :

$v=\sqrt{\mu rg}$

$v=\sqrt{0.39\times 79\times 9.8}$

v = 17.37 m/s

So, the maximum speed of the car is 17.37 m/s.

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4 years ago

1. A point scored when the ball passes between the goal posts is considered a

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Answer:

Goal or Field Goal

Explanation:

It is a goal in a sport like hockey or it is a field goal in football.

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3 years ago

Show that the entire Paschen series is in the infrared part of the spectrum. To do this, you only need to calculate the shortest

mr_godi [17]

Answer and Explanation:

The computation of the shortest wavelength in the series is shown below:-

$\frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )$

Where

$\lambda$ represents wavelength

R represents Rydberg's constant

$n_f$ represents Final energy states

and $n_i$ represents initial energy states

Now Substitute is

$1.097\times 10^7\ m^{-1}\ for\ R, \infty for\ n_i,\ 3 for\ n_i,\\\\\ \frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )$

now we will put the values into the above formula

$= 1.097\times 10^7 m^{-1}(\frac{1}{3^2} - \frac{1}{\infty^2} )\\\\ = 1.097\times10^7\ m^{-1} (\frac{1}{9} )$

$= 1218888.889 m^{-1}$

Now we will rewrite the answer in the term of $\lambda$

$\lambda = \frac{1}{1218888.889} m\\\\ = 0.82\times 10^{-6} m$

So, the whole Paschen series is in the part of the spectrum.

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4 years ago

What are the characters associated with light as a wave

Liono4ka [1.6K]

Answer:

Interference of light

Diffraction of light

Polarization of light

Reflection of light

all show the wave nature of light.

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3 years ago

In which situation would an object weigh the LEAST? (assume all the objects have the same mass)

inessss [21]

Answer:

An object on the moon would weigh the LEAST among these. So correct answer is B.

Explanation:

Weight of an object on any place is given by:

W = Mass * Acceleration due to gravity(g)

It means when masses of different objects those are in different places are same, the weight of those objects depends upon the 'g' of that particular place.

As we know, acceleration due to gravity on surface of moon (g') is 6 times weaker than the acceleration on surface of earth (g), which is due to the large M/R^2 of the earth than the moon.

i.e. g' = g/6 so W' = W/6

And in the space between the two, the object is weightless.

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3 years ago

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