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12345 [234]
3 years ago
5

Consider the general reaction: 2 A + b B → c C and the following average rate data over a specific time period \Delta t: - \frac

{ \Delta A}{\Delta t} = 0.0080 mol L-1 s-1 - \frac{ \Delta B}{\Delta t} = 0.0120 mol L-1 s-1 \frac{ \Delta C}{\Delta t} = 0.0160 mol L-1 s-1 Determine what the coefficient c could be in the balanced equation. Select one: 1 5 2 3 4
Chemistry
1 answer:
lawyer [7]3 years ago
7 0

Answer:

c = 4

Explanation:

In general, for the reaction

       a A     +    b B     ⇒ c C   +    d D

the rate is given by:

rate = - 1/a ΔA/Δt = - 1/b ΔB/Δt = + 1/c ΔC/Δt = + 1/d ΔD/Δt

this is done so as to express the rate in a standarized way which is the same to all the reactants and products irrespective of their stoichiometric coefficients.

For this question in particular we know the coefficient of A and need to determine the coefficient c.

- 1/2 ΔA/Δt = + 1/c ΔC/Δt

- 1/2 (-0.0080 ) = + 1/c ( 0.0160 mol L⁻¹s⁻¹ )

0.0040 mol L⁻¹s⁻¹  c = 0.0160 mol L⁻¹s⁻¹

∴ c = 0.0160 / 0.0040 = 4

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Determine the molarity of 50 mL of HCl solution with unknown concentration, titrated with 75 mL of 4.0 M NaOH.
Aleks04 [339]

Answer:

The answer to your question is 6.0M, I know that you said it was not the answer, but it is. Check the significant figures.

Explanation:

Data

Molarity = ?

volume of HCl = 50 ml

volume of NaOH = 4 M

volume = 75 ml

Balanced chemical reaction

        HCl  +  NaOH  ⇒  NaCl  +  H₂O

Process

1.- Calculate the moles of NaOH

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2.- Use proportions to calculate the moles of HCl

                 1 mol of NaOH ----------------- 1 mol of HCl

                0.3 moles of NaOH ----------  x

                 x = (0.3 x 1)/1

                 x = 0.3 moles of HCl

3.- Calculate the molarity of HCl

Molarity = 0.3/0.05

Molarity = 6.0 M

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