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suter [353]
3 years ago
11

How much physical activity should an adult have each week?

Physics
1 answer:
sergiy2304 [10]3 years ago
8 0
I believe the correct answer is c
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A car drives at a constant speed of 21 m/s around a circle of radius 100 m.
Arte-miy333 [17]

Answer:

Option D. 4.4 m/s²

Explanation:

The following data were obtained from the question:

Velocity (v) = 21 m/s

Radius (r) = 100 m

Centripetal acceleration (a) =.?

The centripetal acceleration of the car can be obtained as follow:

Centripetal acceleration (a) = Velocity square (v²) / radius (r)

a = v²/r

a = 21²/100

a = 441/100

a = 4.41 ≈ 4.4 m/s²

Therefore, the centripetal acceleration of the car is 4.4 m/s².

8 0
3 years ago
Circular coil 1 has N turns and circular coil 2 has 6N. Coil 1 has area A and coil 2 has area A/4. If Coil 1 has current i runni
solmaris [256]

Answer:

\frac{L_1}{L_2} =\frac{1}{3}

Explanation:

Recall that the formula for an inductance (L) for coil on N turns, are A and current I is given by:

L=\frac{\mu_0\,N^2\,A}{I}

Then, for the first coil we have;

L_1=\frac{\mu_0\,N^2\,A}{I}

and for coil 2 we have:

L_2=\frac{\mu_0\,(6\,N)^2\,(A/4)}{3\,I}

then, the quotient L1/L2 can be written as:

\frac{L_1}{L_2} =\frac{\mu_0\,N^2\,A\,3\,I}{\mu_0\,(6\,N)^2\,(A/4)\,I}=\frac{12}{36} =\frac{1}{3}

7 0
3 years ago
WILL GIVE BRAINLIEST ASAP
Sedaia [141]

Explanation:

1. Height Relatives to reference point, Mass, and strength of the gravitational field it's in

2. Distance in the magnetic field

8 0
3 years ago
The number of times a machine multiplies the effort force is the what of the machine
mylen [45]
"<span>The number of times a machine multiplies the effort force is the what of the machine" 
Work Output is the answer, I believe.</span>
7 0
4 years ago
If a car has a velocity of 85 km/hr, how long will it take to accelerate to 45 km/hr if the acceleration is -3 km/hr/sec?
weqwewe [10]

Answer:

Time, t = 13.34 seconds.

Explanation:

Given the following data;

Initial velocity, u = 85km/hr to meters per seconds = 85*1000/3600 = 23.61 m/s

Final velocity, v = 45km/hr to meters per seconds = 45*1000/3600 = 12.5 m/s

Acceleration, a = -3 km/hr/sec to meters per seconds square = -3*1000/3600 = -0.833m/s²

To find the time;

Acceleration = (v - u)/t

-0.833 = (12.5 - 23.61)/t

-0.833t = -11.11

t = 11.11/0.833

Time, t = 13.34 seconds.

6 0
3 years ago
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