Answer:
20 N
Explanation:
<em>Newton's second Law of motion</em> law states that If there is a external force acting on an object. Then the rate of change of momentum of that object is directly proportional to the force acting on its.
- the net force acting upon the object <em>(F)</em>
- the mass of the object. <em>(m)</em>
- <em>V </em>Final velocity of the object
- U initial velocity of the object
- mV -Final momentum of the object
- mU - Initial momentum of the object
Due to momentum change of that object, momentum change. We can write the equation bellow this,
F = (mV-mU)/t
When m is constant we can write the above expression like this,
F = m (V-U)/t
There for
(V-U)/t = a ( Rate of change of velocity can be denoted as acceleration )
F = m× a
we can state this in mathematically,
a = F/m
in another representation
F = m*a
Net Force = mass*acceleration
= 10 * 2
= 20 N
object is subjected to a negative acceleration due to the friction.
Answer: The drag force goes up by a factor of 4
Explanation:
The <u>Drag Force</u> equation is:
(1)
Where:
is the Drag Force
is the Drag coefficient, which depends on the material
is the density of the fluid where the bicycle is moving (<u>air in this case)
</u>
is the transversal area of the body or object
the bicycle's velocity
Now, if we assume
,
and
do not change, we can rewrite (1) as:
(2)
Where
groups all these coefficients.
So, if we have a new velocity
, which is the double of the former velocity:
(3)
Equation (2) is written as:
(4)
Comparing (2) and (4) we can conclude<u> the Drag force is four times greater when the speed is doubled.</u>
The centripetal force is:
F = mv² / R
Where:
m: mass of the object
v: object speed
R: radius of the curve.
We have to:
m = 2000kg
v = 25 m / s
R = 80 meters.
Then the centripetal force acting on the vehicle is:
F = (2000kg * (25m / s) ²) / 80m
F = 15625 N
the path of an electron around the nucleus of an atom
Answers:
a) -171.402 m/s
b) 17.49 s
c) 1700.99 m
Explanation:
We can solve this problem with the following equations:
(1)
(2)
(3)
Where:
is the bomb's final jeight
is the bomb'e initial height
is the bomb's initial vertical velocity, since the airplane was moving horizontally
is the time
is the acceleration due gravity
is the bomb's range
is the bomb's initial horizontal velocity
is the bomb's fina velocity
Knowing this, let's begin with the answers:
<h3>b) Time</h3>
With the conditions given above, equation (1) is now written as:
(4)
Isolating
:
(5)
(6)
(7)
<h3>a) Final velocity</h3>
Since
, equation (3) is written as:
(8)
(9)
(10) The negative sign ony indicates the direction is downwards
<h3>c) Range</h3>
Substituting (7) in (2):
(11)
(12)