How much physical activity should an adult have each week?

How do I find the magnitude of the net force acting on the box

prohojiy [21]

Answer:

20 N

Explanation:

<em>Newton's second Law of motion</em> law states that If there is a external force acting on an object. Then the rate of change of momentum of that object is directly proportional to the force acting on its.

the net force acting upon the object <em>(F)</em>
the mass of the object. <em>(m)</em>
<em>V </em>Final velocity of the object
U initial velocity of the object
mV -Final momentum of the object
mU - Initial momentum of the object

Due to momentum change of that object, momentum change. We can write the equation bellow this,

F = (mV-mU)/t

When m is constant we can write the above expression like this,

F = m (V-U)/t

There for

(V-U)/t = a ( Rate of change of velocity can be denoted as acceleration )

F = m× a

we can state this in mathematically,

a = F/m

in another representation

F = m*a

Net Force = mass*acceleration

= 10 * 2

= 20 N

object is subjected to a negative acceleration due to the friction.

4 0

3 years ago

The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the drag force?

timurjin [86]

Answer: The drag force goes up by a factor of 4

Explanation:

The <u>Drag Force</u> equation is:

$F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2}$ (1)

Where:

$F_{D}$ is the Drag Force

$C_{D}$ is the Drag coefficient, which depends on the material

$\rho$ is the density of the fluid where the bicycle is moving (<u>air in this case) </u>

$A_{D}$ is the transversal area of the body or object

$V$ the bicycle's velocity

Now, if we assume $C_{D}$ , $\rho$ and $A_{D}$ do not change, we can rewrite (1) as:

$F_{D}=C.V^{2}$ (2)

Where $C$ groups all these coefficients.

So, if we have a new velocity $V_{n}$ , which is the double of the former velocity:

$V_{n}=2V$ (3)

Equation (2) is written as:

$F_{D}=C.V_{n}^{2}=C.(2V)^{2}$

$F_{D}=4CV^{2}$ (4)

Comparing (2) and (4) we can conclude<u> the Drag force is four times greater when the speed is doubled.</u>

7 0

3 years ago

A car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s per second. The curve has a radiu

IrinaK [193]

The centripetal force is:
F = mv² / R
Where:
m: mass of the object
v: object speed
R: radius of the curve.
We have to:
m = 2000kg
v = 25 m / s
R = 80 meters.
Then the centripetal force acting on the vehicle is:
F = (2000kg * (25m / s) ²) / 80m
F = 15625 N

4 0

2 years ago

What is a electron orbit?

Advocard [28]

the path of an electron around the nucleus of an atom

5 0

3 years ago

Read 2 more answers

An airplane is moving at 350 km/hr. If a bomb is

Molodets [167]

Answers:

a) -171.402 m/s