According to above question ~
Let's find the charge (q) by using formula ~
Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds
Answer:
No, it is not proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinder.
Explanation:
A cylinder is said to be infinitely long when is of a sufficient length. Also, when the diameter of the cylinder is relatively small compared to the length, it is called infinitely long cylinder.
Cylindrical rods can also be treated as infinitely long when dealing with heat transfers at locations far from the top or bottom surfaces. However, it not proper to treat the cylinder as being infinitely long when:
* When the diameter and length are comparable (i.e have the same measurement)
When finding the temperatures near the bottom or top of a cylinder, it is NOT PROPER TO USE AN INFINITELY LONG CYLINDER because heat transfer at those locations can be two-dimensional.
Therefore, the answer to the question is NO, since it is not proper to use an infinitely long cylinder when finding temperatures near the bottom or top of a cylinder.
If the length and linear density are constant, the frequency is directly proportional to the square root of the tension.
Answer:
1.64 * 10^(-5) m
Explanation:
Parameters given:
Angular separation, θ = 0.018 rad
Wavelength, λ = 589 nm = 5.89 * 10^(-7) m
The angular separation when there are 2 slots is given as
θ = λ/2d
where d = separation between slits
d = λ/2θ
d = (589 * 10^(-9))/(2 * 0.018)
d = 1.64 * 10^(-5) m
