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spayn [35]
3 years ago
13

F = ma

Physics
2 answers:
tekilochka [14]3 years ago
6 0
The correct answer is A
k0ka [10]3 years ago
4 0

Answer:

A. 6000N

Explanation:

Force=mass*acceleration

Force=3000kg*2 m/s

6000N=3000kg*2 m/s

hope this helps!

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which of the following helps to explain why you can lift heavy objects more easily when they are in water
lara [203]

Buoyancy from water. Buoyancy is an upward force on an object immersed in a fluid (i.e., a liquid or a gas), enabling it to float or at least to appear lighter.

3 0
3 years ago
A 5.30 g bullet moving at 963 m/s strikes a 610 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
Tems11 [23]

Answer:

a) V_{wf} = 4.67m/s

b) V = 8.29 m/s

Explanation:

Givens:

The bullet is 5.30g moving at 963m/s and its speed reduced to 426m/s. The wooden block is 610g.

a) From conservation of linear momentum

Pi = Pf

m_{b}V{b_{i} }  + V_{wi}  = m_{w} V_{wf} + m_{b}V_{bf}

where m_{b},V{b_{i} are the mass and the initial velocity of the bullet, m_{w} and V_{wi} are the mass and the initial velocity of the wooden block, and V_{wf} and V_{bf} are the final velocities of the wooden block and the bullet

The wooden block is initial at rest (V_{wi} = 0) this yields

m_{b}V{b_{i} }  = m_{w} V_{wf} + m_{b}V_{bf}

By solving for V_{wf} adn substitute the givens

V_{wf} = \frac{m_{b}V_{bi} - m_{b} V_{bf}    }{m_{W} }

= \frac{5.3(g)(963(m/s)-426(m/s) }{610(g)}

V_{wf} = 4.67m/s

b) The center of mass speed is defined as

V = \frac{m_{b} }{m_{b}+m_{w} } V_{bi}

substituting:

V = \frac{5.3(g)}{5.3(g)+610(g)} X 963(m/s)

V = 8.29 m/s

7 0
3 years ago
Brainliest for correct answer! :)
Katena32 [7]

Answer:

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2. 873.15

3. 221.95

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Find the magnitude of the sum of these two vectors: B 101 m 60.0 ° 85.0 m A​
slamgirl [31]

Answer:

M= 161.1 m Deg= 32.9

Explanation:

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2 years ago
What are the applications of pascal's principle​
Murrr4er [49]

Explanation:

  • The applications are, hydraulic lift- to transmit equal pressure throughout a fluid.
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