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Neko [114]
3 years ago
8

Once he reach the bottom of the hill he slides across the ground horizontal.it takes him 20 seconds to slow down from his speed

at the bottom of the hill to stop what is his acceleration when he sliding horizontally?
Physics
1 answer:
natita [175]3 years ago
7 0

His acceleration is

<em>(-0.05) · (his speed at the bottom of the hill) </em>m/s²

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The terrestrial planets and the giant planets have different compositions because
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The terrestrial planets are closer to the sun.

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Which subatomic particle has the least mass?
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3 years ago
A car enters a freeway with initial velocity of 15.0 m/s and with con stant rate of acceleration, reaches a velocity of 22.5 m/s
LiRa [457]

Answer:

a) The acceleration is 2.14 m/s^{2}

b) The distance traveled by the car is 65.61 m

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Explanation:

Using the equations that describe an uniformly accelerated motion:

a) a=\frac{v_f - v_o}{t} =\frac{22.5m/s - 15.0 m/s}{3.50s}

b) d= d_0 + v_0 t + \frac{1}{2} a t^{2} = 0 +15.0 x 3.5 + \frac{2.14x3.50^{2} }{2} = 65.61 m

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8 0
4 years ago
Lillian (mass 40.0 kg) standing at rest on slippery ice catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Wha
mestny [16]

Answer:

0.82 m/s

Explanation:

From the law of conservation of momentum,

Total momentum = Final momentum.

mu+m'u' = V(m+m')......................... equation 1

Where m = mass of Lillian, u = initial velocity of Lillian before she catches the dog, m' = mass of the dog, u' = initial velocity of the dog, V = velocity of Lillian and the dog.

make V the subject of the equation,

V = (mu+m'u')/(m+m')................ Equation 2

Given: m = 40 kg, m' = 15 kg, u = 0 m/s (Lillian was standing at rest), u' = 3.0 m/s.

Substitute into equation 2

V = (40×0+15×3)/(40+15)

V = (0+45)/55

V = 45/55

V = 0.82 m/s

3 0
4 years ago
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