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s344n2d4d5 [400]
3 years ago
15

Por que el movimiento de un auto que recorre una pista circular ni es M.R.U.V​

Physics
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

Salta al contenido principal

Contenido principal

Movimiento rectilíneo uniforme (MRU)

Movimiento Rectilíneo

Movimiento rectilíneo uniforme (MRU)

Imagina que eres un astronauta en la Estación Espacial Internacional. Estás arreglando unos paneles solares averiados, cuando de pronto, al presionar, tu destornillador sale disparado de tus manos. Si no lo atrapas a tiempo, el destornillador estará viajando por el espacio en línea recta y a velocidad constante, a menos que algo se interponga en su camino. Esto sucede porque la herramienta se mueve con movimiento rectilíneo uniforme, o MRU.

Foto de la Estación Espacial Internacional

Foto de la Estación Espacial Internacional

Estación Epacial Internacional orbitando nuestro planeta. Créditos: International Space Station orbiting above earth de la National Reconnaissance Office.

El MRU se define el movimiento en el cual un objeto se desplaza en línea recta, en una sola dirección, recorriendo distancias iguales en el mismo intervalo de tiempo, manteniendo en todo su movimiento una velocidad constante y sin aceleración.

Recuerda que la velocidad es un vector, entonces, al ser constante, no varía ni su magnitud, ni su dirección de movimiento.

Condiciones del MRU

Para que un cuerpo esté en MRU, es necesario que se cumpla la siguiente relación:

t−t

0

x−x

0

Constante

Donde

xxx: es la posición en el espacio y

ttt: es el tiempo.

De esta condición, llegamos a la ecuación del MRU:

x = x_0 + v(t-t_0)x=x

0

+v(t−t

0

)x, equals, x, start subscript, 0, end subscript, plus, v, left parenthesis, t, minus, t, start subscript, 0, end subscript, right parenthesis

Donde:

\Large x_0x

0

x, start subscript, 0, end subscript: posición en el instante \Large t_0t

0

t, start subscript, 0, end subscript

\Large xxx: Posición en el instante \Large ttt

Esto quiere decir que si conocemos la posición x_0x

0

x, start subscript, 0, end subscript en el instante t_0t

0

t, start subscript, 0, end subscript y sabemos cuál es la de la velocidad vvv, podremos conocer la posición xxx en cualquier instante ttt.

¡No olvides fijarte bien en las unidades que utilizas y de convertirlas si es necesario!

Veamos un ejemplo:

Imagínate que has programado un carro robótico para que tenga una velocidad constante ¿Puedes calcular a qué distancia desde el punto de partida estará luego de 30\text{ s}30 s30, start text, space, s, end text?

Tienes los siguientes datos:

v

x

0

t

0

t

=10 m/s

=0 m

=0 s

=30 s

Explanation:

espero y esto te ayude

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soldi70 [24.7K]
Friction plays a roll of operation in a car because we u stop pressing the peddle friction slowly starts making you slow down and stop.
3 0
4 years ago
Suppose A = B"Cm, where A has the dimensions LT, B has dimensions L²T-1, and C has dimensions LT2. Then the exponents n and have
tresset_1 [31]

Complete Question:

Suppose A = B^n C^m, where A has the dimensions LT, B has dimensions L²T⁻¹, and C has dimensions LT². Then the exponents n and m have the values

Answer:

The value of n = ¹/₅

The value of m = ³/₅

Explanation:

Given dimensions;

A = LT

B = L²T⁻¹

C = LT²

The values of n and m are calculated as follows;

LT = [L^2T^{-1}]^n[LT^2]^m\\\\L^1T^1 = [L^{2n}T^{-n}]\times [L^mT^{2m}]\\\\L^1 \times T^1 = [L^{(2n+m)}] \times [T^{(-n +2m)}]\\\\1 = 2n + m -----(1)\\\\1 = -n + 2m ----(2)\\\\from  \ (1); \ m = 1-2n, \ \ substitute \ the \ value \ of \ m \ in\  (2)\\\\1= -n +2(1-2n)\\\\1 = -n + 2-4n\\\\1-2 = -5n\\\\-1 = -5n\\\\1= 5n\\\\n = \frac{1}{5} \\\\m = 1 - 2n\\\\m = 1 - 2(\frac{1}{5} )\\\\m = 1- \frac{2}{5} \\\\m = \frac{3}{5}

8 0
3 years ago
For every 120 joules of energy input a car wastes 85 joules , find the useful energy output of the car ?
Tamiku [17]

Answer:

35 Joules

Explanation:

Applying

Input Energy(Q) = Useful energy output(U)+Wasted Energy(W)

Q = U+W.............................. Equation 1

Make U the subject of the equation

U = Q-W................... Equation 2

From the question,

Given: Q = 120 Joules, W = 85 Joules

Substitute these values into equation 2

U = 120-85

U = 35 Joules

6 0
3 years ago
Tarzan is testing the strength of a particular vine, which is 7 m long. As he is hanging on the vine, what is the magnitude of t
pentagon [3]

Answer:

the tension generated on the vine is equal to 784.8 N

Explanation:

As Tarzan is testing the strength of vine

to test the vine Tarzan hangs on it.

given,

mass of Tarzan  = 80 kg

acceleration due to gravity = 9.81 m/s²

tension on the wire will be            

     T = m × g                    

     T = 80 kg × 9.81 m/s²                

     T = 784.8 kg.m/s²                

     T = 784.8 N                    

hence, the tension generated on the vine is equal to 784.8 N

3 0
3 years ago
Use the periodic table to answer the question
True [87]

Answer: I hope this helps you

Explanation:

8 0
3 years ago
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