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horsena [70]
3 years ago
10

SO NOT HALAL MODE :(

Chemistry
1 answer:
amid [387]3 years ago
5 0

Answer:

umm

Explanation:

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A mountaineer shouts for help Half a second later (0.5 she hears the echo How far away is the rock face which is reflecting her
irinina [24]

Answer:

THE DISTANCE OF THE ROCK REFLECTING HER VOICE IS 82.5 METERS.

Explanation:

In sound waves, the speed of a sound is equal to twice the distance divided by time.

Mathematically,

Speed = 2 * Distance/ Time

Speed = 33- m/s

Time = 0.5 second

Distance = unknown

So re-arranging and introducing the variables into the formula, we have;

Distance = speed * time / 2

Distance = 330 * 0.5 / 2

Distance = 82.5 meters.

The distance away from the rock face which is reflecting her voice is 82.5 meters.

7 0
4 years ago
A chemist has a 12.5 liter sample of neon gas at 1.00 atm and 30 c. If the chemist compresses the sample to 10.5 liters and hold
ycow [4]

Answer:

254.5 K

Explanation:

Data Given

initial volume V1 of neon gas = 12.5 L

final Volume V2 of neon gas = 10.5 L

initial Temperature T1 of neon gas = 30 °C

convert Temperature to Kelvin

T1 = °C +273

T1 = 30°C + 273 = 303 K

final Temperature T2 of neon gas = ?

Solution:

This problem will be solved by using Charles' law equation at constant pressure.

The formula used

                        V1 / T1 = V2 / T2

As we have to find out Temperature, so rearrange the above equation

                       T2 = V2 x T1 / V1

Put value from the data given

T2 = 10.5 L x 303 K / 12.5 L

T2 = 254.5K

So the final Temperature of neon gas = 254.5 K

8 0
3 years ago
If a stock solution of 20.0 g of sugar per 100. ml of solution is available, how much of this stock is needed to prepare 10.0 ml
Vladimir79 [104]

You must use 2.50 mL of the concentrated solution to make 10.0 mL of the dilute solution.

We can use the dilution formula

<em>V</em>_1<em>C</em>_1 = <em>V</em>_2<em>C</em>_2

where

<em>V</em> represents the volumes and

<em>C</em> represents the concentrations

We can rearrange the formula to get

<em>V</em>_2 = <em>V</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>V</em>_1 = 10.0 mL; <em>C</em>_1 = 5.00 g/100. mL

<em>V</em>_2 = ?; ____<em>C</em>_2 = 20.0 g/100. mL

∴ <em>V</em>_2 = 10.0 mL × [(5.00 g/100. mL)/(20.0 g/100. mL)] = 10.0 mL × 0.250

= 2.50 mL

3 0
3 years ago
What is between the cornea and iris
joja [24]
The cornea is the outer clear, round structure that covers the Iris and the pupil. The Iris is the colored part of the eye.
4 0
4 years ago
80 POINTS!!! ALL PLATO USERS: asap!!!
Crank

This year course engages students in becoming skilled readers of prose written in a variety of periods, disciplines, and

rhetorical contexts and in becoming skilled writers who compose for a variety of purposes. More immediately, the course

prepares the students to perform satisfactorily on the A.P. Examination in Language and Composition given in the spring.

Both their writing and their reading should make students aware of the interactions among a writer’s purposes, audience

expectations, and subjects as well as the way generic conventions and the resources of language contribute to effectiveness

in writing. Students will learn and practice the expository, analytical, and argumentative writing that forms the basis of

academic and professional writing; they will learn to read complex texts with understanding and to write prose of

sufficient richness and complexity to communicate effectively with mature readers. Readings will be selected primarily,

but not exclusively, from American writers. Students who enroll in the class will take the AP examination.

4 0
4 years ago
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