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Luda [366]
3 years ago
8

Identify the element that cannot participate in nuclear fission reactions.

Chemistry
1 answer:
ioda3 years ago
6 0

Answer:

h

Explanation:

You might be interested in
4.
Evgen [1.6K]

Answer:

λ = 2.8 m

Explanation:

Given data:

Frequency of radio wave = 106.7 ×10⁶ Hz

Wavelength of radio wave = ?

Solution:

Formula:

Speed of wave = frequency  × wavelength

speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s = 106.7 ×10⁶ Hz × λ

Hz = s⁻¹

λ = 3×10⁸ m/s / 106.7 ×10⁶ Hz

λ =  3×10⁸ m/s / 106.7 ×10⁶ s⁻¹

λ =  0.028×10² m

λ = 2.8 m

7 0
2 years ago
If the volume of 0.100M HCl delivered to 10.0mL of NaOH is 12.0mL the NaOH concentration is
iVinArrow [24]
<span>During neutralization reaction Milliequivalent of acid=milliequivalent of base. Milliequivalent of HCl=0.100*12*1 Milliequivalent of NaOH=M*10*1 So 0.100*12*1=M*10*1 Solve for M.</span>
3 0
3 years ago
Anyone have any ideas on what i should draw for my art project please let me know
Goryan [66]

Answer:

A pumpkin or a deer cus it's hunting season

5 0
3 years ago
Read 2 more answers
Classical bonding in NaH2PO4
lesantik [10]

NaH_2PO_4, a crystal structure with a short symmetrical hydrogen bond.

<h3>What is Classical bonding?</h3>

Classical models of the chemical bond. By classical, we mean models that do not take into account the quantum behaviour of small particles, notably the electron. These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.

Sodium dihydrogen phosphate is a derivative composed of glycerol derivatives formed by reacting mono and diglycerides that are derived from edible sources with phosphorus pentoxide followed by neutralization with sodium carbonate.

Bonding in NaH_2PO_4

NaH_2PO_4, a crystal structure with a short symmetrical hydrogen bond. Sodium dihydrogen phosphate (NaH_2PO_4) is monoclinic, space group P2,/c, with a= 6.808 (2), b= 13.491 (3), c=7.331 (2)/~, fl=92.88 (3) ; Z=8.

Learn more about the bond here:

brainly.com/question/10777799

#SPJ1

7 0
2 years ago
Element m reacts with fluorine to form an ionic compound with the formula mf4. the m cation has 18 electrons. element m is:____.
polet [3.4K]

Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

<h3>What is Ionic Compound ?</h3>

An ionic compound is defined as the compound made up of ions that formed charge particles when an atom loses or gains electrons.

<h3>What is Cation ?</h3>

Cations are positively charged ions. It forms when an element lose one or more electrons.

The cation which has 18 electrons is Sn. Sn react with fluorine to form an ionic compound with the formula SnF₄ because Sn is large and F is very small in size.

Thus from the above conclusion we can say that Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

Learn more about the Ionic Compound here: brainly.com/question/2687188

#SPJ1

6 0
2 years ago
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