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Luda [366]
3 years ago
8

Identify the element that cannot participate in nuclear fission reactions.

Chemistry
1 answer:
ioda3 years ago
6 0

Answer:

h

Explanation:

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What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
kompoz [17]

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of Al(OH)_3 = 0.610 g

Molar mass of Al(OH)_3 = 78 g/mol

\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

By Stoichiometry,

1 mole of  Al(OH)_3 reacts with 3 moles of HCl

So, 0.0078 moles of Al(OH)_3 will react with \frac{3}{1}\times 0.0078 = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

0.0234moles=\frac{\text{Given mass}}{36.5g/mol}

Mass of HCl required will be = 0.8541 grams

3 0
3 years ago
What is the ph of a very acidic solution?
Nadya [2.5K]

Answer:  

pH = -1

Explanation:

A solution of 10 mol·L⁻¹ HCl is very acidic.

HCl is a strong acid, so it dissociates completely in water and

[\text{H}_{3}\text{O}^{+}] = \text{10 mol/L}

To get the pH, you take the negative logarithm of the hydronium ion concentration.  

\text{pH} = -\log{(10)} = -1\\

So, a pH = -1 represents a very acidic solution.

8 0
3 years ago
1. In apothecaries' measures: 1 scruple = 20 grains, 1 ounce = 480 grains, 1 oz = 28.34 g
laila [671]

Answer:

5.89 g × 10⁶ μg

Explanation:

Step 1: Convert 5.00 scruples to grains

We will use the conversion factor 1 scruple = 20 grains.

5.00 scruple × 20 grain/1 scruple = 100 grain

Step 2: Convert 100 grains to ounces

We will use the conversion factor 1 oz = 480 grains.

100 grain × 1 oz/480 grain = 0.208 oz

Step 3: Convert 0.208 oz to grams

We will use the conversion factor 1 oz = 28.34 g.

0.208 oz × 28.34 g/1 oz = 5.89 g

Step 4: Convert 5.89 g to micrograms

We will use the conversion factor 1 g = 10⁶ μg.

5.89 g × 10⁶ μg/1 g = 5.89 g × 10⁶ μg

4 0
3 years ago
The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process. In the first step, manganese(I
ale4655 [162]

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:  

Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\

Equation:  

3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\

Calculating the amount of MnCO_3

= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\=  13.1 \ kg

For point b:

Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\  of\  Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\

=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg

Equation:  

3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\

Calculating the amount of MnO_2:  

= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\=  6516 \ g \\\\=6.52 \ kg\\\\

7 0
3 years ago
1. What is the relationship between base pairs A, C, T, and G in determining an individual's
tensa zangetsu [6.8K]

Answer:

The base pairs are what makes up an individual's genes.

Check below for further explanation.

Explanation:

The base pairs A, C, T and G are the basic molecules which makes is the DNA of individual.

The genes of an individual which determines the phenotypical expressions found in an individual such as eye colour, height, etc, are functional units found in the DNA.

Therefore, the arrangement of the base pairs determines the gene present in an individual and thus, the individual's phenotype.

3 0
3 years ago
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