The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.
<h3>
Angular velocity of the tire</h3>
The angular velocity of the tire is the rate of change of angular displacement of the tire with time.
The magnitude of the angular velocity of the tire is calculated as follows;
ω = 2πN
where;
- N is the number of revolutions per second
ω = 2π x (5.25 / 3)
ω = 11 rad/s
<h3>Tangential velocity of the tire</h3>
The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.
The magnitude of the tangential velocity is caculated as follows;
v = ωr
where;
- r is the radius of the car's tire
v = 11r m/s
Learn more about tangential velocity here: brainly.com/question/25780931
Answer:
T = 1.1285 10⁻² day
Explanation:
For this exercise the forces in the premiere are internal, so the angular momentum is conserved
L₀ = I₀ w₀
L = I w
L₀ = L
I₀ w₀ = I w
Angular velocity and period are related
w₀ = 2π / T₀
w = 2π / T
The moment of inertia of a sphere is
I₀ = 2/5 M R²
I = 2/5 m r²
If we assume that the mass of the star does not change in the transformation
We substitute
2/5 M R² 2π/T₀ = 2/5 M r² 2π/ T
R² /T₀ = r² / T
T = (r / R)² T₀
T = (6.1 / 2.0 104) 37
T = 1.1285 10⁻² day
Answer:
BBbbb
Explanation:
B is the correct answer:))))
Answer:
Weight is a consequence of the universal law of gravitation
Explanation:
Weight, gravitational force of attraction on an object, caused by the presence of a massive second object, such as the Earth or Moon. Weight is a consequence of the universal law of gravitation: any two objects, because of their masses, attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
