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STatiana [176]
3 years ago
10

Complete and balance the following nuclear equations by including the missing particle. You may want to reference (Pages 906 - 9

09) Section 21.2 while completing this problem. Part A 25298Cf+105B → 310n+?
Chemistry
1 answer:
Alja [10]3 years ago
4 0

Answer:

The missing particle is _{103}^{259}\textrm{Lr}.

Explanation:

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

^{252}_{98}\textrm{Cf}+^{10}_{5}\textrm{B}\rightarrow ^A_Z\textrm{X}+3^1_0\textrm{n}

To calculate A:

Total mass on reactant side = total mass on product side

252 +10 = A+ 3

A = 259

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

98 +5 = Z + 0

Z = 103

Hence, the isotopic symbol of unknown element is _{103}^{259}\textrm{Lr}

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A company is developing a new type of airplane that can take off like a helicopter. Before they begin manufacturing the airplane
Black_prince [1.1K]

C, to make sure the design works as expected.

A prototype is first, typical model of the said product. Hope this helps!

6 0
3 years ago
Read 2 more answers
Write both answers to at least two decimal places. Calculate the pH of a 0.160 M solution of KOH.Part 2 (1 point) Calculate the
Evgen [1.6K]

To calculate the pH of a solution, we first need to find the concentration of hydronium ions in the solution. Since KOH is a strong base, it dissociates completely in water to produce hydroxide ions (OH-) and potassium ions (K+).

The concentration of hydronium ions in a solution of KOH can be calculated using the concentration of hydroxide ions and the equilibrium constant for water, which is equal to 1.00 x 10^-14 at 25 degrees Celsius.

The concentration of hydroxide ions in a 0.160 M solution of KOH is equal to the concentration of KOH, which is 0.160 M. The concentration of hydronium ions in the solution can be calculated using the equation below:

[H3O+] = (1.00 x 10^-14) / [OH-]

Substituting the concentration of hydroxide ions into the equation above, we get:

[H3O+] = (1.00 x 10^-14) / (0.160 M) = 6.25 x 10^-13 M

To calculate the pH of the solution, we need to take the negative logarithm of the concentration of hydronium ions. This can be done using the equation below:

pH = -log([H3O+])

Substituting the concentration of hydronium ions into the equation above, we get:

pH = -log(6.25 x 10^-13) = 12.20

The pH of a 0.160 M solution of KOH is 12.20.

To calculate the pOH of a solution, we first need to find the concentration of hydroxide ions in the solution. Since we already calculated this value above, we can simply use the concentration of hydroxide ions we found earlier: 0.160 M.

To calculate the pOH of the solution, we need to take the negative logarithm of the concentration of hydroxide ions. This can be done using the equation below:

pOH = -log([OH-])

Substituting the concentration of hydroxide ions into the equation above, we get:

pOH = -log(0.160 M) = 1.80

The pOH of a 0.160 M solution of KOH is 1.80.

Learn more about pH:
brainly.com/question/28864035

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7 0
1 year ago
what mass of aluminium hydroxide is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry?
pishuonlain [190]
Aluminium Hydroxide on decomposition produces Al₂O₃ and Water vapors. 

<span>                               2 Al(OH)</span>₃    →    Al₂O₃  +  3 H₂O


According to equation at STP,

       67.2 L (3 moles) of H₂O is produced by  =  78 g of Al(OH)₃
So,
                65.0 L of H₂O will be produced by  =  X g of Al(OH)₃

Solving for X,
                                 X  =  (65.0 L × 78 g) ÷ 67.2 L

                                 X  =  75.44 g of Al(OH)₂
Result:
           75.44 g of Al(OH)₂ is needed to decompose in order to produce 65.0 L of water at STP in stoichiometry
6 0
3 years ago
Read 2 more answers
Wastewater from a cement factory contains 0.280 g of Ca2+ ion and 0.0220 g of Mg2+ ion per 100.0 L of solution. The solution den
faltersainse [42]

<u>Answer:</u> The concentration of Ca^{2+}\text{ and }Mg^{2+} ions are 2.797 ppm and 0.212 ppm respectively.

<u>Explanation:</u>

To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Volume of gold = 100 L = 100000 mL    (Conversion factor:  1 L = 1000 mL)

Density of gold = 1.001 g/mL

Putting values in above equation, we get:

1.001g/mL=\frac{\text{Mass of solution}}{100000mL}\\\\\text{Mass of solution}=1.001\times 10^5g

To calculate the concentration in ppm (by mass), we use the equation:

ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

  • <u>Calculating the concentration of calcium ions:</u>

Mass of Ca^{2+ ions = 0.280 g

Putting values in above equation, we get:

ppm(Ca^{2+})=\frac{0.280g}{1.001\times 10^5}\times 10^6=2.797ppm

  • <u>Calculating the concentration of magnesium ions:</u>

Mass of Mg^{2+ ions = 0.0220 g

Putting values in above equation, we get:

ppm(Mg^{2+})=\frac{0.0220g}{1.001\times 10^5}\times 10^6=0.212ppm

Hence, the concentration of Ca^{2+}\text{ and }Mg^{2+} ions are 2.797 ppm and 0.212 ppm respectively.

7 0
3 years ago
What is a physical property of water
Lyrx [107]

Answer:

Water has a lot of physical properties.

Explanation:

One of them is heat of vaporization.

Bam

3 0
3 years ago
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