Answer:
fjrjrnrirjrjjrjrjdiejejjdoajwjdoornrkrjrjroenejdjejjejjeujrjrbdjjendjjdjdjeneoapwnsbqkskennskennejdjeccjrjnrjrbbrjkwkwnnsjwjejjejeniebejjdiejejeiwnekwkiejejejj2jekwkwjekwok2mwnwjenrnowo2p1plaks
B. The sand increases friction by increasing roughness.
Answer:
XCH₄ = 0.461
XCO₂ = 0.539
Explanation:
Step 1: Given data
- Partial pressure of methane (pCH₄): 431 mmHg
- Partial pressure of carbon dioxide (pCO₂): 504 mmHg
Step 2: Calculate the total pressure in the container
We will sum both partial pressures.
P = pCH₄ + pCO₂
P = 431 mmHg + 504 mmHg = 935 mmHg
Step 3: Calculate the mole fraction of each gas
We will use the following expression.
Xi = pi / P
XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461
XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539
The subatomic particle that gives off visible light is electrons
