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andrezito [222]
3 years ago
14

Which of the following statements explains why fossil fuels are nonrenewable resources

Chemistry
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

the first one

Explanation:

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How do I calculate the pH of an 11mL sample of C8H4O4 (a mix of NaOH and KHP) when the ka=1.5x10^-5?​
Len [333]

Answer:

ummm 3?.................

7 0
3 years ago
John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bottle,
enot [183]

One can solve the problem by using the law of conservation of momentum. The total momentum prior to the collision must be equivalent to the total momentum after the collision, so we have:

m1v1 + m2v2 = m1v1 + m2v2

Here, m1 is 0.4 Kg that is the mass of the ball, u1 is 18 m/s that is the initial velocity of the ball, m2 is 0.2 Kg that is the mass of the bottle, and u2 is 0 that is the initial velocity of the bottle.

v1 is the final velocity of the ball, which is to be determined, and v2 is 25 m/s that is the final velocity of the bottle.

Substituting and rearranging the equation, one can find the final velocity of the ball:

v1 = m1u1 - m2v2 / m1 = (0.4 kg) (18 m/s) - (0.2 Kg) (25 m/s) / 0.4 Kg = 5.5 m/s.

5 0
3 years ago
Read 2 more answers
Concentration in ppm containing 30 grams NaNO3 in 70 grams H2O
Reika [66]
110 g at 40°C

See explanation
5 0
3 years ago
How many grams of CaCl2would be dissolved in 1.0 L of a 0.10M<br> solution of CaCl2?
Goryan [66]
Mass of CaCl2=11g
I hope this one is help you

3 0
3 years ago
what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.
In-s [12.5K]

Answer:

\boxed{\text{C. 11.2 L}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 22.4 L; T₁ = 273.15 K

V₂ = ?;         T₂ = 136.58 K

Calculations:

\dfrac{ 22.4}{273.15} = \dfrac{ V_{2}}{136.58}\\\\0.082 00 = \dfrac{ V_{2}}{136.58}\\\\V_{2} =0.082 00 \times 136.58 = \boxed{\textbf{11.2 L}}

5 0
3 years ago
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