Answer:
c = 100 J/g.°C
Explanation:
Given data:
Mass of lime = 20 g
Heat absorbed = 80,000 J
Initial temperature = 10°C
Final temperature = 50°C
Specific heat capacity of lime = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 50°C - 10°C
ΔT = 40°C
80,000 J = 20 g×c×40°C
80,000 J = 800°C×c
c = 80,000 J /800g.°C
c = 100 J/g.°C
Answer:
The number of solute particles increases, and the boiling point increases.
Explanation:
- It is known from colligative properties that adding solute to the solvent will cause elevation of boiling point.
- Elevation of boiling point (ΔTb) can be expressed as:
<em>ΔTb = Kb.m,</em>
where, Kb molal boiling point elevation constant.
m is the molal concentration of solute.
- Adding more sodium chloride to the solution:
will increase the number of solute particles and also will increase the molal concentration of NaCl solute.
<em>∵ ΔTb ∝ m.</em>
- So, the boiling point increases.
- Thus, the right choice is:
<em>The number of solute particles increases,</em>
<em></em>
Answer:- 1945.15 K
Solution:- The given temperature is 1672 degree C and we are asked to convert it to kelvin.
For the conversion of temperature unit degree C to kelvin we add 273.15.
So, 1672 + 273.15 = 1945.15 K
Hence, the melting point of titanium metal would be 1945.15 K.
