Answer:
0.868M Cu⁺
Explanation:
The reaction is:
KMnO₄ + 5Cu⁺ + 8H⁺ → 5Cu²⁺ + Mn²⁺ + K⁺ + 4H₂O
<em>Where 1 mol of KMnO₄ reacts with 5 moles of Cu⁺</em>
<em />
3.30x10⁻²L of 0.132M KMnO₄ are:
3.30x10⁻²L × (0.132mol KMnO₄ / L) = <em>4.356x10⁻³mol KMnO₄</em>
As 1 mol reacts with 5 moles of Cu⁺, moles of Cu⁺ are:
4.356x10⁻³mol KMnO₄ × (5mol Cu⁺ / 1mol KMnO₄) = <em>0.02178moles Cu⁺</em>
As these moles are in 2.51x10⁻²L, the starting concentration of the Cu⁺ solution is:
<em>0.02178moles Cu⁺ / </em>2.51x10⁻²L = <em>0.868M Cu⁺</em>
