In order to solve this graphically, you would construct two lines:

The first of y = √2

The second of y = sec(x)

The solutions will be the intersections over the given domain.

Solving mathematically:

sec x = √2

1/cos(x) = √2

cos (x) = 1/√2

x = -π/4 and π/4

**Answer:**

T=√250 or ≈15.81

**Explanation:**

by dividing both sides by .008, you eliminate .008 on the left side and get 2÷.008=250 on the right. to eliminate the ^2 on T, you need to square root both sides, so on the left it's √T^2=T, and on the right it's √250, or roughly 15.81.

**Answer:**

Plains have a **low **elevation and **low **relief.

**Explanation:**

In geography, elevation and relief are two important terms that are used to define the topography of a region.

**Elevation:**

It is defined as the the height of an area above a reference point like the sea level.

- The elevation of K2 is 8,611 m which shows that K2 has height of 8,611 m above the sea level.

**Relief:**

In geography, relief of an area is defined as the difference between the elevation of the highest points and elevation of the lowest points of that area.

The **rate constant** of first order reaction at 32. 3 °C is 0.343 /s must be less the 0. 543 at 25°C.

First-order reactions are very commonplace. we have already encountered examples of first-order reactions: the hydrolysis of aspirin and the reaction of t-butyl bromide with water to present t-butanol. every other reaction that famous obvious first-order kinetics is the hydrolysis of the anticancer drug cisplatin.

The value of ok suggests the equilibrium ratio of products to reactants. In an equilibrium combination both reactants and merchandise co-exist. big ok > 1 merchandise are k = 1 neither reactants nor products are desired.

Rate constant K₁ = 0. 543 /s

T₁ = 25°C

**Activation energy** Eₐ = 75. 9 k j/mol.

T₂ = 32. 3 °C.

K₂ =?

formula;

log K₂/K₁= Eₐ /2.303 R [1/T₁ - 1/T₂]

putting the value in the equation

K₂ = 0.343 /s

Hence, The **rate constant** of first order reaction at 32. 3 °C is 0.343 /s

The specific rate steady is the proportionality consistent touching on the fee of the reaction to the concentrations of reactants. The fee law and the specific charge consistent for any chemical reaction should be determined experimentally. The cost of the charge steady is temperature established.

Learn more about** activation energy** here:- brainly.com/question/26724488

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Gymnosperm seeds develop either on the surface of scales or leaves, which are often modified to form cones, or solitary as in yew, Torreya, Ginkgo.