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Amiraneli [1.4K]
3 years ago
6

Glucose, c6h12o6, is used as an energy source by the human body. the overall reaction in the body is described by the equation

Chemistry
1 answer:
Art [367]3 years ago
4 0
Glucose is carbohydrate and a simple sugar that is very important to the human body.

Energy is produced for the cells in the body through the process of metabolism which oxidizes glucose to water, carbon dioxide, and some nitrogen compounds. 

The general chemical reaction equation for metabolism is:
 
C6H12O6 + 6O2 ---> 6CO2 + 6H2O 
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3 years ago
A sample has a mass of 35.4g and a volume of 36.82mL. What is the density of the sample
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6 0
2 years ago
Given the equation C3H8(g) + O2(g) = CO2(g) + H2O(g) and that the enthalpies of formation for H2O(g) = -241.8 kJ/mol, CO2(g) = -
kari74 [83]

Answer: 72.4 kJ/mol

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The balanced chemical reaction is,

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)  \Delta H=-2220.1kJ/mol

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_3H_8}\times \Delta H_{C_3H_8})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-2220.1=[(3\times -393.5)+(4\times -241.8)]-[(5\times 0)+(1\times \Delta H_{C_3H_8})]

\Delta H_{C_3H_8}=72.4kJ/mol

Therefore, the heat of formation of propane is 72.4 kJ/mol

7 0
2 years ago
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