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Len [333]
2 years ago
13

Calculate the mass of a solid metal cylinder with a density of 2.6 g/cm", a

Chemistry
1 answer:
worty [1.4K]2 years ago
8 0

Answer:

V= π ×r² × h

V = 3.14 × (0.9)² × 4

V = 3.14 × 0.81 × 4

V = 10.1736

Mass = Volume × density

M = 10.1736 × 2.6

M = 26.45136 g

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ryzh [129]

Answer:

vb

Explanation:

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liam uses a machine that counts waves on a metal cable. The machine counts 25 waves in 2 seconds. what is the frequency of the w
Softa [21]
Frequency is defined as the number of waves per second. In this machine 25 waves pass in one second.
We need to calculate the number of waves that pass a particular point during one second.
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3 years ago
A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0
2 years ago
What is the pH of a solution whose hydronium ion [H20+] (or proton [H+1)
pav-90 [236]

Answer:

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___CH4 + ___O2 → ___CO2 + ___H2O
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CH4 + 2O2 =======> CO2 + 2H2O
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