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Len [333]
3 years ago
13

Calculate the mass of a solid metal cylinder with a density of 2.6 g/cm", a

Chemistry
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

V= π ×r² × h

V = 3.14 × (0.9)² × 4

V = 3.14 × 0.81 × 4

V = 10.1736

Mass = Volume × density

M = 10.1736 × 2.6

M = 26.45136 g

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How many ions in 6.41 moles of K2O? Please show work.
Oksana_A [137]
1. Convert the number of moles to number of particles (divide 6.41 by 6.022 x 10^23)

2. K2O dissociates into three ions (2 potassium ions and 1 oxide ion), so multiply the result from step 1 by 3 to get your answer
4 0
3 years ago
When liquid gold becomes a solid, its particles get closer together. Which best describes what happened to the gold?
yanalaym [24]

Answer:

The rearrangement of particles in a physical change.

Explanation:

When things are liquid the particles tend to be spread out because they aren't tightly compacted as they would be with a solid. So when liquid gold is changing from a liquid to a solid the properties are changing and the particles in the gold are getting closer together.

7 0
3 years ago
Read 2 more answers
Determine if the electron configurations are valid or invalid
Hunter-Best [27]

Answer:

1) A (valid)

2) B (Invalid)

3) B (Invalid)

4) A (valid)

5) B (Invalid)

6) B (Invalid)

Explanation:

Electronic configuration:

The electronic configuration is the arrangnment of electrons in orbitals (s, p, d, f, g, h so on) according to quantum  number and Aufbau rule.

An atom of element have orbitals, and electrons are revolving in it.

There are quantum numbers that describe the number of electron in specific shell.

The Principle quantum number is denoted by "n" and can not be "0".

These "n" is K, L, M, N and electrons are distribution in it.

K =2

L= 8

M= 18

According to Aufbau electron occupied in the lowest energy level before occupying the highest energy level.

According to this the electronic configuration is

1s², 2s², 2p⁶ and so on....

So,

"s" orbital accommodate maximum of 2 electrons

"p" orbital accommodate maximum of 6 electrons

"d" orbital accommodate maximum of 10 electrons

"f" orbital accommodate maximum of 14 electrons

and the coefficient 1, 2, 3, 4 are energy level of orbitals.

The 1st orbital is 1s and it only can occupy 2 electrons the next coming electron goes into 2s that also can occupy 2 electrons and the further electrons will go to 2p orbital.

So keeping in mind all above details we investigate all option one by one

1.  A (valid)

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁵

This is valid option. number of electrons are rightly accommodated in orbitals. Also 3d is higher energy level than 4p.

______________

2.  B (Invalid)

1s², 2s², 2p⁶, 3s², 3p⁷

This is invalid option. number of electrons are not rightly accommodated in orbitals as "p" orbital can only accommodate 6 electrons and not more than 6.

________________

3.  B (Invalid)

[Xe], 7s², 6d¹, 5f⁸

This is Invalid option. Number of electrons are not rightly accommodated in orbitals. There should 5f orbital before 6d.

______________

4.  A (valid)

[Kr] 5s², 4d¹⁰, 5p⁵

This is valid option. number of electrons are rightly accommodated in orbitals.

______________

5.  B (Invalid)

[He]--

This is invalid option. There is no exact explanation of electron distribution in orbitals.

______________

6.  B (Invalid)

1s², 2s², 2p⁶, 3s³, 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s--

This is invalid option. number of electrons are not rightly accommodated in orbitals. As "s" can accommodate only 2 electrons not 3 electrons. also there is no details of 5s

______________

4 0
3 years ago
The number of individuals an environment can sustain for an indefinite period of time is called its
swat32
<span>C. Carry capacity
</span>Carry capacity is defined as the maximum population size of a species that an environment can sustain indefinitely. It is also defined as the environment's maximal load of a species. Factors that impact on the carrying capacity of a species are the availability of food and water, raw materials to build shelter, the environment's ability to process waste products, as well as the species' ability to reproduce. 
7 0
3 years ago
The rate law for the rearrangement of ch3nc to ch3cn at 800 k is rate = (1300 s-1)[ch3nc]. what is the half-life for this reacti
Lana71 [14]
The rate of reaction is always expressed in concentration per time like mol/L·s. The equation is:

r [mol/L·s] = kCⁿ, where n is the order of reaction. Since k is 1300/s, that means that Cⁿ = C such that (1/s)*(mol/L) = mol/L·s. Thus, n=1. For a first order reaction, the formula would be:

ln(A/A₀) = -kt
where
A is the amount of material after time t
A₀ is the amount of material at t=0

The half life is when A/A₀ = 1/2÷1 = 1/2. Thus, the half-life t is:

ln(1/2) = (-1300t)
t = 5.33×10⁻⁴ seconds
3 0
3 years ago
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