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Mashcka [7]
3 years ago
15

A first place finisher in a cross country meet ran 5,000 meters in 871.7 seconds. What was his average speed?​

Chemistry
1 answer:
Serjik [45]3 years ago
6 0

Answer : His average speed was, 5.735 m/s

Solution : Given,

Total distance covered = 5000 meter

Total time taken = 871.7 seconds

Average speed : It is defined as the total distance covered in total amount of time.

Formula used :

\text{Average speed}=\frac{\text{Total distance covered}}{\text{Total time taken}}

Now put all the given values in this formula, we get his average speed.

\text{Average speed}=\frac{5000m}{871.7s}=5.735m/s

Therefore, his average speed was, 5.735 m/s

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the melting point of scandium fluoride is 1552°c, explain why scandium fluoride has a high melting point.​
Greeley [361]

Answer:

Scandium(III) fluoride, ScF3, is an ionic compound. It is slightly soluble in water but dissolves in the presence of excess fluoride to form the ScF63− anion.

hope it will help you......

5 0
3 years ago
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Which of the following is TRUE? A) The equivalence point is where the amount of acid equals the amount of base during any acid-b
liberstina [14]

Answer:

the correct option is B

Explanation:

The correct option is b, since if we reach pH 7, it means that the acid-base reaction is neutralized, therefore the base has been neutralized by an acid or vice versa, without taking into account the proteins or the amounts of both components .

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3 years ago
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Which is an example of making a quantitative observation?
Elanso [62]

Answer:

A) measuring mass of metal used in a reaction

Explanation:

Quantitive observations is data involving statistics and numerical values.

4 0
3 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

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3 years ago
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What components are required for cellular respiration
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