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frosja888 [35]
3 years ago
7

40 points, please help I seriously cannot fail this class and I am extremely confused. All you have to do is solve using dimensi

onal analysis. If you can type some form of work that would be helpful. I will go answer a question on yours as well also.

Chemistry
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

the answer to the first is 5.5 meters :)

You might be interested in
What type of reaction is: 4 Fe + 3 O2 → 2 Fe2O3
Dafna11 [192]

Answer:

A. synthesis

Explanation:

The reaction given is a synthesis reaction in which two substances combines to give a product.

In this reaction:

      4Fe + 3O₂ →  2Fe₂O₃

The reaction involves the formation of a single product from two or more reactants.

The formation of a compound from union of the constituent elements also falls into this category of reaction.

3 0
3 years ago
A sailboat is pushed by a steady wind with a force of 4000 N. Its acceleration is 2
AveGali [126]

Answer:

<h2>2000 kg</h2>

Explanation:

The mass of the sailboat can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{4000}{2}  \\

We have the final answer as

<h3>2000 kg</h3>

Hope this helps you

6 0
3 years ago
A 23.5g aluminum block is warmed to 65.9°C and plunged into an insulated beaker containing 55.0g water initially at 22.3°C. The
atroni [7]

Answer:

25.97oC

Explanation:

Heat lost by aluminum = heat gained by water

M(Al) x C(Al) x [ Temp(Al) – Temp(Al+H2O) ] = M(H2O) x C(H2O) x [ Temp(Al+H2O) – Temp(H2O) ]

Where M(Al) = 23.5g, C(Al) = specific heat capacity of aluminum = 0.900J/goC, Temp(Al) = 65.9oC, Temp(Al+H2O)= temperature of water and aluminum at equilibrium = ?, M(H2O) = 55.0g, C(H2O)= specific heat capacity of liquid water = 4.186J/goC

Let Temp(Al+H2O) = X

23.5 x 0.900 x (65.9-X) = 55.0 x 4.186 x (X-22.3)

21.15(65.9-X) = 230.23(X-22.3)

1393.785 - 21.15X = 230.23X – 5134.129

230.23X + 21.15X = 1393.785 + 5134.129

251.38X = 6527.909

X = 6527.909/251.38

X = 25.97oC

So, the final temperature of the water and aluminum is = 25.97oC

4 0
3 years ago
How to calculate the sum of the ratio of the ions
ANEK [815]
If it is just ratio you must just put the mass number on the either side of the symbol ‘:’ and cancel but the same process is not used to find simplest ratio
6 0
3 years ago
How many grams of magnesium nitride is required to produce 25.00 g of magnesium hydroxide?
Lesechka [4]

Answer:

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

Explanation:

The balanced equation is

Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3

Molecular weight of magnesium nitride = 100.9494 g/mol

Molecular weight of magnesium hydroxide = 58.3197 g/mol

one mole of Mg3N2 produces three moles of 3Mg(OH)2

100.9494 g/mol of  Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2

1 gram of Mg3N2 produces

\frac{3* 58.3197}{100.9494 } \\1.733grams of Mg(OH)2

Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

6 0
3 years ago
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