A rarefraction is generated when particles move A:together B.closer C.under D.apart

Which sample is a pure substance?

Sunny_sXe [5.5K]

A test tube of zinc oxide

6 0

3 years ago

Read 2 more answers

Which two have to do with Movement of Galaxies? (pick 2)

pychu [463]

I don’t see anything

6 0

3 years ago

The cell theory was construted by

NeTakaya

Answer:

Matthias Jakob Schleiden

Explanation:

The cell was initially discovered by Robert Hooke, but Schleiden developed the theory.

Hope this helps! :)

4 0

3 years ago

1.8 mol HCl and 3.3 mol NaOH react accord- ing to the equation HCl + NaOH −→ NaCl + H2O . Calculate the amount in moles of NaCl

ollegr [7]

Answer:

1.8 moles of NaCl must be produced.

Explanation:

Based on the reaction:

HCl + NaOH → NaCl + H2O

1 mol of HCl reacts with 1 mol of NaOH to produce 1mol of NaCl

To solve this question we must find, as first, the limiting reactant:

1.8 moles of HCl will need 1.8 moles of NaOH for a complete reaction (Ratio of reaction 1:1). As there are 3.3 moles of NaOH,

HCl is limiting reactant

When the 1.8 moles of HCl react completely,

1.8 moles of NaCl must be produced because 1 mole of HCl produce 1 mole of NaCl

5 0

3 years ago

What is the molarity of a 1.44 (m/v)% solution of an HCOOOH (Formic acid)?

AlexFokin [52]

This problem is providing the mass-volume percent of a formic acid solution so its molarity is required and found to be 0.313 M after the following calculations.

<h3>Molarity</h3>

In chemistry, units of concentration provide a measurable understanding of the relationship between the relative amounts of both solute and solvent. In the case of molarity, one must relate moles of solute and liters of solution as follows:

$M=\frac{mol\ solute}{Volume\ solution \ in \ L}$

In such a way, when given this mass-volume percent of 1.44% for the formic acid in the solution, one can assume there is 100 mL of solution and 1.44 g of solute (formic acid), which means one must convert the volume to liters and the mass to moles with:

$mol\ solute=\frac{1.44g}{46.03g/mol} =0.0313mol\\\\Volume\ in \liters: 100mL*\frac{1L}{1000mL}=0.100L$

Finally, we plug in these numbers in the equation for the calculation of molarity:

$M=\frac{0.0313mol}{0.100L}\\\\M=0.313M$

Learn more about molarity: brainly.com/question/10053901

8 0

2 years ago