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luda_lava [24]
4 years ago
12

Assessment started: undefined.

Chemistry
2 answers:
Bingel [31]4 years ago
8 0

Answer:

Reactivity

Explanation:

Examples of chemical properties includes toxicity, acidity, reactivity and heat of combustion

myrzilka [38]4 years ago
5 0

It would be Reactivity

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An unknown metal sample has a mass : of 11.29. and a volume of 2 cm3. What is the : density of the unknown metal? ​
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Answer:

\boxed{\sf Density \ of \ the \ unknown \ metal = 5.645 \ g/cm^3}

Given:

Mass = 11.29 g

Volume = 2 cm³

To Find:

Density of unknown metal

Explanation:

Formula:

\boxed{ \bold{Density = \frac{Mass}{Volume}}}

Substituting value of mass & volume in the formula:

\sf \implies Density =  \frac{11.29}{2} \\  \\   \sf \implies Density =  5.645 \: g/cm^3

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What is the value of δg°' (or, to put it another way, the cost) when 2nadp+ and 2h2o are converted to 2nadph plus 2h+ plus o2?
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The answer is 104.9, i dont know how though
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For you last required journal entry of the quarter, but on a separate piece of paper, create a poster which compares the mass of
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With a mole of skittles placed side by side, you can go around the earth <span>191.17 trillion times. 

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</span>(6.022x10^23) x .5" = 3.011x10^23 inches.
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4 years ago
Determine the ΔH for the following reaction 2NH3 + 5/2O2 = 2NO(g) + 3 H2O(g)
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The enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

  • Enthalpy change, ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)

\Delta{H_{f}\:of\:NO = 90.25 kJ; \Delta{H_{f}\:of\:H_{2}O =-241.82kJ;  \Delta{H_{f}\:of\:NH_{3} =-46.1 kJ;  \Delta{H_{f}\:of\:O_{2} =0

\Delta{H_{f}\:of\:rxn = (90.25*2)+(-241.82*3)-( -46.1*2)= -452.76\:kJ

Therefore, the enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

Learn more about enthalpy change at: brainly.com/question/14047927

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